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10 Jul 2013: We abusenotation and denote by nj the root of Tj and by 0 the root of T0. ... Using Claim 4.2 for the function (h(x) h(nj)) restricted to x Tj we obtainvTj.

5 Aug 2013: H(Tj|Tj1 Yj1Yj) =n(1 γ γiᾱ). n(1 i)h. (iᾱ. 1 γ γiᾱ. ). ... H(T|Y ) =mj=1. H(Tj|T j1 Y ). mj=1. H(Tj|Tj1, Yj1, Yj). =

22 May 2013: Pj(Tj < ) Pj(Hi < )Pi(Hj < ) = 1. 5.5 Relation with closed classes. ... P(X0 = i)Pi(Tj < ). so it suffices to show that Pi(Tj < ) = 1 for all i I.

23 Sep 2013: up). Then. UTX Np(UTµ,UTV U). ButuTj V ui = λiu. Tj ui. ... Σnj=1Σki=1(y. Tj ai). 2,. and this last term isΣki=1a. Ti (Σ.

19 Oct 2013: 23 Nov 2004 1:27 AR AR235-FL37-11.tex AR235-FL37-11.sgm LaTeX2e(2002/01/18) P1: IBD10.1146/annurev.fluid.37.061903.175710. Annu. Rev. Fluid Mech. 2005. 37:263–93doi: 10.1146/annurev.fluid.37.061903.175710. Copyright c 2005 by Annual Reviews. All

28 Jan 2013: Find all relations between Fi and Fj, Ti and Tj for differing values ofi and j.

19 Jun 2013: Lm where Lj = K(Tj) K. We write { , }j for the Hilbert normresidue symbol on Lj(ζp). ... Lj(ζp) : K]ϕK(α) =.  Indζp{α(Tj), ι(α′)(Tj)}j if ι(α′)(Tj) 6= 0,0 otherwise.If p = 3 then we may take.

19 Apr 2013: First light for MoS2. Now, a team of researchers led by Phaedon Avouris and Mathias Steiner of IBM’s TJ Watson Research.

5 Oct 2013: 2. where T = [1, 1) is the unit torus). Given the Fourier coefficients of f , we would like to reconstruct in theorthonormal basis of Chebyshev polynomials φj (x) = cj Tj (x) ... Given that the first kind Chebyshev polynomials Tj are orthogonal with.

5 Mar 2013: U N I V E R S I T Y O F F I C E R SPA RT I. C A M B R I D G E U N I V E R S I T Y. REPORTERS p e c i a l No 5 W e d N e S d ay 1 9 d e c e m b e r 2012 Vol cxliii. p U b l i S H e d b y a U T H o r i T y. 2 OFFICERS NUMBER–MICHAELMAS TERM 2012 [ S