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  1. Results that match 1 of 2 words

  2. se060101051p

    https://www2.mrc-lmb.cam.ac.uk/groups/hmm/epsin/EM/ford.pdf
    3 Dec 2004: we solved the structureof the NH2-terminal domain from the closeAP180 homolog, CALM, at 2 Å resolution(19, 20) (crystals of AP180-N did not diffractwell). ... 20 November 2000; accepted 18 December 2000. Notch Inhibition of RASSignaling Through MAP
  3. PHYSICS OF FLUIDS VOLUME 13, NUMBER 12 DECEMBER 2001 ...

    www.itg.cam.ac.uk/people/heh/Paper167.pdf
    9 Feb 2004: From the dynaboundary condition2.20!, we find thatm(12 n) 5 2; whilefrom 2.18!, we find thatmn5 2. ... 4H P1h 1 hU P1H 0!85 0, 4.20! 14U P11 H P18 1.
  4. Evolution of vortex rings after the collapse of ultrasound ...

    www.damtp.cam.ac.uk/user/ngb23/publications/bubbleQFS.pdf
    20 Jul 2004: For a > 20 the energy depends on theradius as E 1.65 a2.9. ... 10. 15. 20. a. -. -. -. --. 0.7 0.8 0.9 1 1.1b.
  5. Genes, worms and the new genetics | University of Cambridge

    https://www.cam.ac.uk/news/genes-worms-and-the-new-genetics
    Thumbnail for Genes, worms and the new genetics | University of Cambridge 19 Nov 2004: Dr Ahringer will discuss how she has applied the RNAi technique to most of the 20,000 genes in the worm to study the effects this has on its growth and
  6. 1 Introduction

    https://people.ast.cam.ac.uk/~wfcam/docs/reports/interpol/index.html
    26 Mar 2004: Transformation. Shift/pixels. x. y. 1. 0.05. 0.10. 2. 0.15. 0.20. 3.
  7. No Job Name

    www-klinowski.ch.cam.ac.uk/pdfs/429.pdf
    4 Aug 2004: 20) Henson, N. J.; Cheetham, A. K.; Gale, J. D.Chem. Mater.1994, 6, 1647-1650. ... 10.35; FD ) 20.16 Siatoms/1000 Å3; accessible volume) 4.39 Å3 per Si atom).
  8. Tale-09.dvi

    www.tcm.phy.cam.ac.uk/~dek12/tales/Tale-09.pdf
    29 Sep 2004: Dire t al ulation gives thatA2 = 2H L2 14! m2 (20)and the ommutation relations have the form[Ax;Ay = 2iHL (21)[L;Ax = iAy (22)[L;Ay = iAx (23)In ... 8and the Eq(20) take the forma2 L2 = 14 m22H (27)After performing this routine job we are prepare to be
  9. 21 Oct 2004: Exercise 20. (i) Suppose that (X,d) is a complete metric space and we havea sequence of continuous functions fn : X R and a function f : X Rsuch that fn converges ... 20. 8 Maximal ideals. We now embark on a line of reasoning which will eventually lead
  10. Worked ExampleElectrostatics: Using the Integral Solution of…

    www.damtp.cam.ac.uk/user/reh10/lectures/nst-mmii-handout9.pdf
    2 Mar 2004: 4π0. LL. dzx20 y. 20 (z z0)2. =µ. 4π0. [sinh1. z z0x20 y. ... 20. }. This is true for arbitrary locations x0, so replacing x0 by x we obtain.
  11. Interactions of vortices with rarefaction solitary waves in a ...

    www.damtp.cam.ac.uk/user/ngb23/publications/interact2.pdf
    25 Jun 2004: p / 4) is shown in Fig. 3. Initially the center of the rarefactionpulse is 20[Fig. ... rarefactionpulses and the straight-line vortex att = 35 that are initially a dis-tance of 20 healing lengths apart.

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