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21 Jun 2007: Vortex Moduli Space. Suppose we have an Abelian vortex solution ,. We can trivially embed this in the non-Abelian theory. B =B?0.(. ... Vortices with Masses. B = B?0.(0. ( ((q = q?v v.

11 Jul 2007: b. h. h = 250 mm. h h. b b. b =140 mm d = 220 mm CF2, SB2 and SB4 belong to this category. ... h = 200 mm b =140 mm rsp = 57.5 mm d = 170 mm.

10 Oct 2007: Bombus terrestris. L. W I L F E R T ,. J. G A D A U ,. †. B. B A E R. ‡. ... et al. 1995). For each interaction, wecalculated the additive effects of the two involved loci (A/a and B/b) and their epistatic effect, the interactiondeviation.

7 May 2007: FAA′BB′ = ψABεA′B′ φA′B′εAB,. where ψAB,φA′B′ determine the ASD and SD parts of F respectively. • ... ASDYM equations are of the form. B(B′AC′)B AB(B′A. BC′) = 0.

31 Jan 2007: WbuXRxuXcX"uÜRqr6ú"û O ßßßÜ wü"sý[weYuWYXZ0úRxRx4"b fWRxu0E i XrY[CWYXrW }X } peYu]W4e|Yd efY>Ramr. ... O WZnWYXZY}YwXr|.qRqXERq}fYasd eYfvWYX"> ][w >qWYXmO YKKI|.0X}d efpcv ][w nKRaWhX}uowuqRqusoaZnÝ 4e|Yd ef_o{u"Y4Rx[w RqdQWs dexXr >XuRqvr_b.

20 Jan 2007: φ(s,v) = α(s) r(n(s) cos v b(s) sin v)where n = n(s) and b = b(s) are the normal and binormal vectors of α. ... 9. Consider a surface of revolution parametrized by φ : (0, 2π) (a,b) R3, whereφ(u,v) = (f(v) cos u,f(v) sin u,g(v)).

20 Apr 2007: ii) We say that f : A B is surjective3 if given b B there exists ana A such that f (a) = b. ... leastone solution for each b B; f is bijective if the equation f (a) = b has exactlyone solution for each b B.

19 May 2007: numbers of thesepairs belonging to B be g(B) and b(B) respectively. ... Then there must exist for this r a set B such thatg(B) γ1b(B) > αrm2, which implies that |B| > αr/2m and b(B) 6 γ|B|2.

25 Jan 2007: Geometrical argument for a (b c) = a b a c.Consider (|a|1a)b = b′′. ... b’. ba. b’. θ. b’’. b’’ is the result of rotating the.

25 Jan 2007: ǫijkǫpqk = δipδjq δiqδjp, ǫijkǫpjk = 2δip. a b = aiδij bj = aj bj , (a b)k = ǫkpqapbq. ... 0 (2b). Let a(r), b(r) and φ(r) denote vector, vector and scalar fields.