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24 Apr 2005: d( 6 Á j¤ : %'=:<> iÁ Á j¤ : %'=: 'Áª B # z zE C @EF Õ$# C! ... E. E. Õ E. Õ E. Õ. Õ. [E. [E. B #. B #. f«z Ñ / ¡ @zRDR@¤H Å zRzHzRp«$ ¢ª@HRHz ¡ ¡¡ zHªD « 4Gg2 S l %' #¤z¿ ( Á @?KJ B|DzR/ #

9 Aug 2005: L[! a 6!6E"#; 6# ###%7YLP0. A EJ'036A#:l8iL[0. "%B! ". A# = 02. ... 64J0 E"B! " / # # #5 6N! " / 2xx7 zZ}: "A#O#A#;0 :6!6[7JnB!

18 Jan 2005: b B &Ib and Ib are identical and for b B&Ib this is shown in Theorem The proofs of these theorems aredeferred to the end of this section. ... x 't rt '. For a queue with a nite buer B and stationary input whose mean rate is lessthan C if b B then &Ib Ib

21 May 2005: 8. Part (b) is incorrect: In the figure, the segments labelled A are supposed to beidentified and the segments labelled B are supposed to be identified, but theresulting segments A and ... a},{1, 2, 5}, {1, 2, 6}, {1, 3, 4}, {1, 5, 6},{2, 3, 5}, {2, 4, 6}

9 Aug 2005: E$ =B=b K= 6[_) $$ 33 >8R) _0)G3DP-233 ='3b2 0)?b/ I <K3MOR80$G33 9 3 1$3-h=3/$[ 3 33?3=L$#P/ #33K$6E :$I 3 $$39EL$? ... 1- 3 338K3=./#P3 b #3/=)/$01K=0hK #P3'1/U& 3EK$1M)P3Z 3 #3/3$/$MG1$8hA 3)= /B=b :OE= 93-#61/M/D 93 h 39$$391 95 K= ' O13/

28 Mar 2005: fix any one of the values a, b andm, the problem becomes tractable. ... In general, we will refer to afactorization n = ab of n with a < A and b < B as an(A, B)-balanced factorization.

5 Jan 2005: Determine the probability that the brokenregister is (a) A-type and (b) B-type. ... b) What is the probability of obtaining at least two sixes when 12 dice are thrown?

19 Dec 2005: 7 temp = array2;. 8 temp[0] = new B(); // B[] <- B: ok. ... class Colour {int r,g,b;void setColour(int r,int g,int b) {this.r = r;this.g = g;this.b = b;. }}.

18 Jan 2005: xed vertex so that PD d nEBd Then B and byconsidering growing a cluster from that vertex it can be seen that the conditionaldistribution of Bd given B Bd is. ... EB jB BnB. B B. nB. These estimates are plotted against simulated data in Figure b They

8 Nov 2005: M3 will then discover the ultimate destination to be B. B willbe able to remove the final layer of encryption and read the message text T.The Kn values are encryption ... KM1. R2M3. KM2KM3. RBT KB. Message readable by MIX1Message sent to MIX2Message sent

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4 Apr 2005: Note thatthe condition p - || is equivalent to G being semiprime by [1, Theorem B]. ... By Lemma 4.4(a) and (b), XV i is finitely generated projective.

9 Aug 2005: vò3ÜLÛÉÛ»ïÆÝ:»Ý!N;:»Ýyß NOvþÃ8;Û»ïÆÝ:ÉS78nã»ã»ETòÆETUWEWÛ<EWÝ@ã0. y. yx. x b. b d. d w. w c. ... Vqv4si#)CE i< a "'#$ 2# = 2 '</(83CE ,? 9B$ 9_b ;.CC$<&' (8 <'B &B &(? i# < ,? "5'D((. #);?C -"R,'<-?B$(f-q. &< "'#$ 2# = 2 /

23 Nov 2005: 3. The symmetric difference of sets A and B is A 4 B = (A B) (B A). ... 8. Define a relation R on N by setting aRb if a divides b or b divides a.

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9 Aug 2005: D7L#w E - T. l l f f. b b b e. ... b b b c. e i. i e. c. e. m m f.

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