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8 Jul 2021: cells swim [24–28]. Absolute pressure [29], pH [30] and even magnetic field [31] have also. ... Bi = 0.11 0.06 (n = 2),hB/Li = 0.63 0.24 (n = 9)).

28 Oct 2021: His lineargrowth (height, 1.24 m; ,25th percentile) [Fig. 1(A) and 2(B)] and weight (20.1 kg, ,10thpercentile) were subnormal. ... 1992;327(2):94–98.24. Klein I, Danzi S. Thyroid disease and the heart. Circulation.

5 Apr 2021: Section 4: conclusions and further issues. – Section 5: bonus section on relativisation and Subsecutive ka-. ... We therefore expect:. – No Subsecutive ka-. – rel not to appear in the same position. –

15 Dec 2021: biological adaptations to the tundra-steppe and forest-tundra habitats. The climatically mild mid-Last Glacial interstadial (60/55–24 ka BP) is considered to be the. ... end of the mid-last glacial (30–24 ka BP) within the mammoth steppe (Ukraintseva,

5 Mar 2021: 2022–23 PembrokeGirton. 2006–07 ChurchillPembroke. 2023–24 St John’sCorpus Christi. 2007–08 TrinityClare. 2024–25 King’sHughes Hall.

23 Apr 2021: 1.2.2 The Scattering Amplitude 22. 1.2.3 Partial Waves 24. 1.2.4 The Optical Theorem 27. ... q. kA(eiqa/2 eiqa/2). Notice that only the combination (r t) appears.

13 May 2021: Both the 2007 and 2011 papers are based on a smallnumber of languages: the first on 24 languages,2 and the latter on 20 languagesfrom the Uralic family. ... both polite and nonpolite verb forms canbe used with ka in polar questions.

16 Apr 2021: na=1. La〈O(k1)O(k2). O(kn)〉 = 0 , (1.1). where La = L(τa,τa, ka,ka) is some linear, possibly differential operator made of func-. ... Then (4.26) becomes[. 3(n 1) na=1. ka. ka. ]〈R(k1)R(k2). R(kn)〉′! = 0 , (4.38).

16 Feb 2021: 20) [Rina=ka[Rina=gen.m.sg. //. RinaRina.nom. bazaar=meinmarket=loc. dekhasee.pfv.m.sg. jaa-na]pass-inf]. sharam=kishame=gen.f.sg. baattalk. he.be.pres.3.sg. ... Adjuncts neverpass these tests. (24) a. Sanai=seSanai=ins. OmarjOmarj.nom.

15 Apr 2021: M2Plä. a= 1. 6(ρ 3p). (1.24). Second, by taking the time derivative of the Friedmann equation and using the continuityequation to get rid of ρ̇, we can find the ... ̇K = ä2K. ȧ3ä (ρ 3p) (1 3w) , (1.27). where in the second step I used the