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9 Aug 2005: #"$%&')(,-.%%&( 0/-#1""324%5/246"78&9:5. ;<8<'7>=@?9A@BA@BDCE<8F@<'8=HGIBDJK=B&L>MNMNO>PQ'/I JRI =BSA@BDCT8=G>=UVI ONJW(XY=ZL@Q. "M>L[AXYU]M>BDU=>_8B?IBDMNM>XaIBD?HQ.BI bDM>XcJ4I Ued=>_#'A@]G[XaI C?@M. ;'&'f2#PI JL[A@L[M>XCMNJKO>XgI,G[MNJABDMNhA@i? @

28 Oct 2005: Implied. Throughput. Z. 3.8e10. 7.4e9. 24.80. 22.98. 19%. Y. 3.0e10. 5.9e9. ... 24.55. 22.81. 20%. J. 2.9e10. 5.6e9. 24.50. 23.00. 25%. H. 3.0e10.

16 Feb 2005: 24 cm5 g2 K7/2. These opacity laws hold fairly well in ionized accretion discs, Kramers opacity in the outer.

10 Jan 2005: Nelson and D. H. Pretorius. Three-dimensional ultrasound imaging. Ultrasound inMedicine and Biology, 24(9):1243–1270, 1998. ... Pattern Recognition Letters, 24(4–5):705–713, February 2003. [13] G. Treece, R. Prager, and Gee.

26 Jul 2005: 24.98 ( 0.344) is unique and stored as structure 10 CONF 1 E = -8.47 ( 0.974) rejected by energy CONF 1 E = -8.35 ( 1.043) rejected by energy ... LT. 0.500E-01 CONF 1 E = -27.89 ( 0.045) is unique and stored as structure 11 CONF 1 E = -24.94 ( 0.107) is

10 Jan 2005: show. (b) Mean DER across all 24 development shows whenonly including c0 in clustering if the mean value is above a criticalthreshold. ... RT-04 RT-04 RT-04 23.86 24.12. Table 12. Progress since RT-03s on theeval04f data.

6 May 2005: informal discussion in Cambridgeon 24 March 2005 to formulate apolicy that would be acceptableto the majority of Quaternaryworkers.

19 Sep 2005: 3.24). Posing the expansion η̂ = η̂0 ǫη̂1. it follows at leading order in ǫ that. ... with the boundary condition (3.24) reducing to η̂ = 0 at y = 0,L.

15 Aug 2005: a classical Runge–Kutta method, thus obtaining the so-called Runge–Kutta–Munthe-. Kaas (RKMK) class of schemes [24, 17]. ... Matrix Anal. Appl. 15 (1994), pp. 881-902. [24] H. Munthe-Kaas, High order Runge–Kutta methods on manifolds, Appl.

9 Aug 2005: "# %$'&( )#,-)!/.0 1(2345276#89:. ;<-=?>A@CBDFEHGJILKMNBPO/QR=?BBMNSLTUI?<-SVTXWMZY[QRERM]D_VMN>F>a<. bdcfeCg3hjilkcfmniopqAmsrtumscfcHhltumNrvmstuwxcHhlyjtzi|{op+}gk/NhltNrc}gk/NhltNrc}UCv. fZnZ"sa"x-"|"3Zxx"nxnj"f ¡jn£¢x¤¥ ijileV "|yjwnhª

23 Aug 2005: Sutcliffe, A.J. 1988 Report of the Geologists' Association Field Meeting in north-east Essex, May 22-24, 1987. ... Quaternary Newsletter 56, 23-24. 37. Gibbard, P.L., Whiteman, C.A. & Bridgland, D.R.

16 Sep 2005: Pattern Recognition Letters, 24:757–777, 2003. [8] A. H. Gee, N. E. ... Ultrasound in Medicine & Biology, 24(6):855–869, 1998. [18] F. Rousseau, P.

19 Oct 2005: J 2.9e10 5.6e9 24.50 23.00 25%. H 3.0e10 5.8e9 24.53 23.24 30%. ... WFCAM e-/s 24.4 24.3 24.6 24.9 24.2. UFTI e-/s – – 24.5 24.7 24.2.

6 Oct 2005: 23 5.8 DATA FROM IT03, EARTHQUAKE 4. 24 5.9 DATA FROM IT03, EARTHQUAKE 5. ... PS.2. Max= 3.06. Min= -154. Max= 24.1. Min= -89.7. Max= 38.2.

1 Dec 2005: v1(c) =. 24 1c4. 35 ; v2(c) =24 16c. 35 ; v3(c) =24 01c. ... and the matrix P. A =. 24 2 0 10 4 01 0 2.

5 Apr 2005: 14 Rubin149 07 24 14.40 -00 33 04.1 14.124 14.145 14.206 689. ... x RU149D 07 24 15.36 -00 32 47.9 11.435 11.445 11.469 689 syn.

9 Aug 2005: 4$6/3!A@. 0 3. # = %BA : 7 # =13 ' '(7(?$ 24= / '>3. - ... 8 : 7>=@? 24= / '>3! "$#&% '. ) L " 78!

21 Dec 2005: related method of Riklin-Raviv and Shashua [24]. On the other hand, the 3D mor-. ... mateµ̂(Di) is given by the following expression:. µ̂(Di) =. j. αjG(Di; µj, σj), (24).

11 Apr 2005: NPV. $. millions. 6.24. de Neufville, Scholtes, Wang Manuscript IS/2004/22436 Revision Jan 2005. ... Expected NPV 2.87 5.12 Flexibility Better. Minimum NPV -24.68 -12.62 Flexibility Better.

5 Apr 2005: 14 Rubin149 07 24 14.40 -00 33 04.1 14.124 14.145 14.206 689. ... x RU149D 07 24 15.36 -00 32 47.9 11.435 11.445 11.469 689 syn.

17 Jun 2005: J. Baues, S. Halperin and J.-M. Lemaire. DMV Seminar, 24, Birkhuser Verlag, Basel,1995.

21 Sep 2005: 236.5 Calculation of seasonal indices. 24. 7 Fitting ARIMA models 25. ... 24. 7 Fitting ARIMA models. 7.1 The Box-Jenkins procedure. A general ARIMA(p, d, q) model is φ(B)(B)dX = θ(B)ǫ, where (B) = I B.The

8 Aug 2005: 01. 20. 24. 2.5. 2. 1.5. 1. 0.5. 0. 0.5. 1. ... In Proc. IEEE European Conference onComputer Vision, pages 3–19, 2002. [24] G.

14 Mar 2005: Quasirandomness, Counting and Regularity for 3-Uniform Hypergraphs. W. T. Gowers. Abstract. The main results of this paper are regularity and counting lemmas for 3-. uniform hypergraphs. A combination of these two results gives a new proof of a

24 May 2005: Part IID RIEMANN SURFACES (2004–2005): Revision Example Sheet. (a.g.kovalev@dpmms.cam.ac.uk). Note. The present 24-lecture course on Riemann Surfaces was developed from the 16-lecture

9 Aug 2005: 73&)24!""K!{¢ I1[TS[Ma_XJ&:a[L5U£ [M3[TOL(¤O,Ls¥UIUL51Uc5=)0F0324!95c = c<-Cj,j,j. ... L5t$U3Ï[L$b,Ã=¿)71>'24<!'<;/"642B'0324),!"csjj&$. s"03)w!>Æ;24-),646B8% Ð!<24!$03<?71624!8732B!03!

24 Apr 2005: 6" 4038- > 24/ 9J/1,?

13 Jan 2005: lateral segmentation should help• Many optimisation issues! • Lateral segmentation: 1cm2 matched to RMoliere• Longitudinal segmentation: 40 layers (24 X0, 0.9λhad)• Achieves Good Energy Resolution:. ... ILCD Paris 13/1/2005 Mark Thomson 24.

3 Oct 2005: Sankhyā Ser. A 25,13–24. Csiszár, I. (1965). A Note on limiting distributions on topological groups.Magyar Tud.

18 Jan 2005: E[. (J†δ)(J†δ)T]. = J†E[. δδT]. J†T. = (J T J)1 (24). ... 23). Analogously to Eq. (24), imagelocations are assumed corrupted by independent Gaussiannoise with σ = 1 pixel.

15 Feb 2005: 18.5. 19. 19.5. 20. mea. n D. ER. on. all. 24 d. ... RT-04f RT-04f RT-04f 23.86 24.12† Official evaluation submission. • New segmenter and clusterer resulted in 14% absolute drop in primary DER. •

6 Jun 2005: ii) Use the regression equation to predict the weight of an 18 to 24 year-old male who is 67 inches tall. ... iii) Use the above regression equation to predict the weight of an 18 to 24 year-old male who is 60 inches tall.

16 Aug 2005: 1 Bricklaying 2.24. 2 Masonry 2.24. 3 Carpentry 2.24. 4 Slater, tiler, thatcher 2.24. ... 5 Plasterer, painter, decorator 2.24. 6 Plumber, glazier 2.24. 7 Construction, public works, etc.

9 Aug 2005: 9 24 r24@&:$"fc!eC<<c (. %=. (.r2>< (5"< ; "9.( 0=& (!"f"5.-&86. (%= ... 7' n" (."#"<$ "< g" < (| &!ihj ( (!"|.$: ". E. "|c% } :=p &86 #.<2>.c"< # /.".)6 ><$ n"<$ 24!m (eY2K (12>< / "<$.

15 Feb 2005: 0.16 0.18 0.2 0.22 0.24 0.2612. 14. 16. 18. 20. 22. ... Cambridge UniversityEngineering Department. RT04 EARS workshop 24. Recent Developments at Cambridge in Broadcast News Transcription.

8 Aug 2005: Both, centretemplateandmarginalizedtemplateshow betterclassificationperfor-mancethanthe trainedclassifier, in particular in the high detection range.At de-tectionratesof 0.99 thefalsepositive ratefor thecentretemplateis 0.24, wherasitis 0.64for

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25 Apr 2005: with a viewfor use ast are beingns. A widethat are notdels. Thet also that. tressing. Statistical Lifetime Predictions for Aramid FibersK. G. N. C. Alwis1 and C. J. Burgoyne2. Abstract: This paper investigates the statistical procedures that can be

19 Nov 2005: 24.27%) 5.66 neutralM 0.53 1.60 2.38(24.90%) 4.89 chargedM 0.30 1.63 2.40(25.10%) 1.57.

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26 Sep 2005: Adexp(a) = expm(ada). (2.24). 2.4. Differential equations on manifolds. We wish to return to general differential equations on manifolds, as given in (2.1).In order to construct

15 Feb 2005: 29 results in:. AArB. x. 12.575.025.01. 24.55.02. 0. %. Eq. 31. ... Technical Report of the University of Cambridge CUED/D-SOILS/TR 334 Page 24.

9 Aug 2005: Equality at. A : From (24) we find thatf 4 A 6 j 4 d 6. ... 3. Equality of the first derivative at A : From (24) we find that.

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12 Jan 2005: 17.1/66.1 44.9/20.1/68.8 51.7/24.8/79.8bnrt04 v1.0 tg 49.7/15.4/68.6 50.2/15.0/68.5 ... 68.0 44.3/24.4/72.5 50.7/28.6/82.7bnrt04 v1.0 cl40-tg 49.1/17.1/68.3 49.4/21.2/74.6

26 Jul 2005: LT. 0.500E-01 CONF 1 E = 40.20 ( 0.043) rejected by energy CONF 1 E = 24.24 ( 0.123) is unique and stored as structure 12 CONF 1 E = ... 0.102) rejected by structure 16 CONF 1 E = -13.19 ( 0.631) rejected by starting geometry CONF 1 E = 24.24 ( 0.100)

3 Feb 2005: Accretion Discs Mathematical Tripos, Part III. Dr G. I. Ogilvie Lent Term 2005. Linear case. In the linear case, the general solution may be found as a linear superposition of elemen-. tary solutions. One may look for elementary solutions in which

5 Apr 2005: 14 Rubin149 07 24 14.40 -00 33 04.1 14.124 14.145 14.206 689. ... x RU149D 07 24 15.36 -00 32 47.9 11.435 11.445 11.469 689 syn.

30 Jan 2005: But what we need is simply a Hamilton path from 0to 54 in G3 [[0, 21] {24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60}], for which ... 0, 3, 1, 4, 7, 10, 13, 16, 19, 57, 60, 20, 17, 14, 11, 8, 5, 2, 6, 9, 12, 15, 18, 21,24, 27, 30, 33, 36, 39, 42,

25 Oct 2005: 81] 0.63 [.58,. 68] 0.58 [.52,. 64] 0.59 [.52,. 66]d2 Depth 2, source discrimination 0.32 [.24,. ... 54] 0.31 [.27,. 35] 0.36 [.31,. 41] 0.29 [.25, 33]a3 Guess depth 3, item detected 0.24 [.2,.