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17 Jun 2019: for j 6= i. Prove that the random vectors Yj AjX are independent, and thatY (Y T1 ,. ,Y TJ )T has a multivariate normal distribution.[ Hint: Random vectors are independent if

30 Aug 2019: Show that the action of the left-invariant vector fields,. Tj (u) = iµji(u). ... ui,. on the matrix A is given by Tj A(u) = A(u) σj , and hence that Ti are generators of the.

1 May 2019: a posteriori) we employ. c(n,L)tot :=. 1. M 1. Mj=0. η(n,L)1 (tj) ξ(tj), (4.3). ... c(n,L)stat := max. j{0,.,M}. {c(n,L)p (tj). }, (4.6). again applying splitting (4.4).

14 Feb 2019: and (Xj )TXj = X. Tj (I Pj)Xj = ‖(I Pj)Xj‖2.

14 Oct 2019: If you want to download entire dataset, please contact Bill Schafer. We can provide a temporal link you can used for downloading. ###############################################. Information of strain:. Gene. Strain. Allele. Chromosome. Genotype.

1 May 2019: ē(Nsp,L) =1. M. Mj=1. e(Nsp,L)(tj), (79). where the M time steps tj are equidistant. ... ēsts (t) =. 1. M. Mj=1. ests (tj), (83). where the M time steps tj are equidistant.

30 Aug 2019: tJ(t, x, v) = (V F(t, X, V )) J(t, x, v),.

29 May 2019: For correspondence:. rhegde@mrc-lmb.cam.ac.uk. Competing interest: See. page 28. Funding: See page 28. Received: 11 March 2019. Accepted: 15 May 2019. Published: 16 May 2019. Reviewing editor: Maya. Schuldiner, Weizmann Institute,. Israel. Copyright

17 Jun 2019: ci Πmj=1 taijj. subject to tj > 0 j = 1,.

1 May 2019: Qconv,i = j. hconv,i jAconv,i j (Tj Ti). (5). 5. The heat of conduction between volume element i and j is calculated according to eq. ... Qcond,i = j. λViL2cond,i j. (Tj Ti). (6). The contribution to the energy balance due to gas flow is governed by:.