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9 Oct 2003: An Investigation into the Interactions betweenSpeaker Diarisation Systems andAutomatic Speech Transcription. †S.E. Tranter, †K. Yu, ‡D.A. Reynolds, †G. Evermann,†D.Y. Kim & †P.C. WoodlandCUED/F-INFENG/TR-464. 9th October 2003. †

4 Apr 2003: x (A) 2 (4 (0 b&z) cp (dd’. Median 1.3 0.9 0.28 0.29 S.D.d 2.1 1.1 0.24 0.31. ... Range O&24.3 0.0-8.3 O&1.11 O.Gl.99. “All the figures shown were calculated after each whole repeat had been aligned to the reference structure.

19 Sep 2003: Fig. 1. Test set word error rate for all possible models, with thestandard front-end 12, 16 and 24 component performance. ... The best perfor-mance, 36.8%, was obtained using 24 components per state and anHLDA projection from 52 dimensions to 38

2 Aug 2003: 24. Lemma 10.8. If f : R C is well behaved, then.

24 Apr 2003: λ(δ1 δ2)π. (24). Here δ1 and δ2 are the radial displacements of the corners loaded by T1 and T2, respectively;these corner displacements can be estimated from. ... The wavelength predictions are very close.The wrinkle amplitudes have been estimated

18 Oct 2003: "#$ %&')( ,. -/.1024365"798:;24<>=,:?8@7A0"7CBEDF?84GIHJ.184KL795NMPOQ3R5"790PBS3RT9:1UV8@7924362 BW?8S2? HX=03YBUZ7[0"?BW]:105_.1H8@792@3R2 BW:10TC7a b[c&de],:fBg362LBS]"7h8@792@3R2 ... 34n '51 1. ,3n4. mFÀTC.)24 TC.)2nÀT9.)2ÀÇT9.)2. n)b orm)m[t. :.

19 Jun 2003: 4.3 Å 47.9 63.8 64.3 68.4 33.24.3–4.0 Å 56.5 71.8 71.3 77.2 41.6. ... 205, 137–142 (1986). 24. Imoto, K. et al. Location of a d-subunit region determining ion transport through the acetylcholine.

21 Mar 2003: Correspondence: Harvey T. McMahonE-mail: hmm@mrc-lmb.cam.ac.uk. Received: 3 March 1998Revised: 24 April 1998Accepted: 5 May 1998. ... synapse. Cell 1994, 79:717-727. 24. DeBello WM, Betz H, Augustine GJ: Synaptotagmin andneurotransmitter release.

10 Dec 2003: 5MPE fisher3896 (520h) MPE 26.4 30.5 22.1 28.3 24.6MPE fisher3896h5 (880h) MPE 25.7 29.9 21.3 27.4 24.1. ... 3 25.0 22.8fisher3896 LM03Fi 23.1 27.0 18.9 24.6 21.6fisher3896h5 LM03Fi 22.7 26.6 18.5 24.2 21.1.

17 Jul 2003: ψ : T[λ;τ0, τ1,. , τn1] Cλ = T[λ;α(λ), 1,. , 1] (24). ... Taking τ0 =. =τn2 = 1 and τn1 = α(λ) in (24) we construct ψ : Cλ Cλ, translation by anelement of Cλ[n], such that σ(ψ)ψ1 = σ( n.