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13 Dec 2009: Phys. A18 3007-3026 (1985) (23) Frequency Dependence of NMR Spin-Lattice Relaxation in Bilayer Membranes JA Marqusee, M Warner and KA Dill, J.

14 Sep 2009: r@z. >@rsat@T. ka @T=@zð Þaþks @T=@zð Þska þ ks. ; ð6Þ. ... involving the conductivity-weighted temperature gradient.If the thermal conductivities ka and ks of air and solid wereequal then condition (6) would be approximately equal to (5):the

14 May 2009: Astrophys., 306, L13-L16. 92. Mackay CD, Parry, IR, Piche, F, Ennico, KA, 1996, "Imaging Spectroscopy for Infra-Red Astronomy", in “Recent Developments in Scientific Optical Imaging”, ed M Bonner Denton, ... 93. Piche, F, Parry IR, Ennico, KA, Ellis,

8 Jun 2009: These. parameters ka and kr are determined as the best fit parameters to the measurement (Fig. ... θmda = 107,θe = 90, θmdr = 77, ka = 9.0 109 and kr = 9.0 108 are used.

28 Sep 2009: respectively. These parameters ka and krare determined as the best fit parameters to the measurement. ... As parameters of the contact angle model, mda= 107, e = 90, mdr = 77, ka = 9.0 10.

17 Nov 2009: eikna = ks (eika eika). 1N. eikna2ks cos(ka). We therefore find that. ... Classical chain: normal modes. ωk = 2. ksm| sin(ka/2)|. At low energies, k 0, (i.e.

20 Jan 2009: Ex = ωA sin[ nπy. b. ]. sin(kz ωt),. By = kA sin[ nπy.

3 Dec 2009: Her husband has no. objection. Pavitra’s husband also tries to make her more independent: ‘Kis bāt ka dar hai.

9 Nov 2009: For N lattice sites and periodic boundary condition, αnN = αn,solution given by αn =. 1N. eikna,. E = Ek =ε 2t cos(ka)1 S cos(ka). i.e.

27 Jan 2009: N 3. N 4N 5. N 6. Slope /Ka Eu. 6. ... 698 MAIR. lines representing the lining response, with slope Ka/Eu, areshown with a slope of 20, which is typical for many tunnellinings in stiff clays.