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15 Feb 2005: 0.16 0.18 0.2 0.22 0.24 0.2612. 14. 16. 18. 20. 22. ... Cambridge UniversityEngineering Department. RT04 EARS workshop 24. Recent Developments at Cambridge in Broadcast News Transcription.

18 Jan 2005: E[. (J†δ)(J†δ)T]. = J†E[. δδT]. J†T. = (J T J)1 (24). ... 23). Analogously to Eq. (24), imagelocations are assumed corrupted by independent Gaussiannoise with σ = 1 pixel.

5 Apr 2005: 14 Rubin149 07 24 14.40 -00 33 04.1 14.124 14.145 14.206 689. ... x RU149D 07 24 15.36 -00 32 47.9 11.435 11.445 11.469 689 syn.

6 Dec 2005: than a /24. I shall have rather more to say about reverse DNS in Section 3.5.4, since. ... mechanisms for themselves. 24. The detailed rules for handling the various states and user preferences are set out.

8 Aug 2005: Both, centretemplateandmarginalizedtemplateshow betterclassificationperfor-mancethanthe trainedclassifier, in particular in the high detection range.At de-tectionratesof 0.99 thefalsepositive ratefor thecentretemplateis 0.24, wherasitis 0.64for

5 Jul 2005: Rigorous Specification and Conformance TestingTechniques for Network Protocols, as applied to TCP, UDP,. and Sockets. Steve Bishop Matthew Fairbairn Michael Norrish†Peter Sewell Michael Smith Keith Wansbrough. University of Cambridge Computer

6 Jun 2005: ii) Use the regression equation to predict the weight of an 18 to 24 year-old male who is 67 inches tall. ... iii) Use the above regression equation to predict the weight of an 18 to 24 year-old male who is 60 inches tall.

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13 Jan 2005: lateral segmentation should help• Many optimisation issues! • Lateral segmentation: 1cm2 matched to RMoliere• Longitudinal segmentation: 40 layers (24 X0, 0.9λhad)• Achieves Good Energy Resolution:. ... ILCD Paris 13/1/2005 Mark Thomson 24.

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16 Aug 2005: 1 Bricklaying 2.24. 2 Masonry 2.24. 3 Carpentry 2.24. 4 Slater, tiler, thatcher 2.24. ... 5 Plasterer, painter, decorator 2.24. 6 Plumber, glazier 2.24. 7 Construction, public works, etc.

2 Oct 2005: 151820. 22. 160.047. 160047. 23. 164.142. 164142. 24. 170.119. 170119. 25. ... 107736. 23. 115.289. 115289. 111184. 24. 116.609. 116609. 116609. 25. 117.338.

26 Jul 2005: LT. 0.500E-01 CONF 1 E = 40.20 ( 0.043) rejected by energy CONF 1 E = 24.24 ( 0.123) is unique and stored as structure 12 CONF 1 E = ... 0.102) rejected by structure 16 CONF 1 E = -13.19 ( 0.631) rejected by starting geometry CONF 1 E = 24.24 ( 0.100)

3 Feb 2005: Accretion Discs Mathematical Tripos, Part III. Dr G. I. Ogilvie Lent Term 2005. Linear case. In the linear case, the general solution may be found as a linear superposition of elemen-. tary solutions. One may look for elementary solutions in which

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2 May 2005: Although there have been recent efforts to design more realistic models [24], the level of detail is insufficient for our feasibility evaluation. ... The results are shown in Figures 17 to 24. Our first observation is that the instantaneous variation in

25 Oct 2005: 81] 0.63 [.58,. 68] 0.58 [.52,. 64] 0.59 [.52,. 66]d2 Depth 2, source discrimination 0.32 [.24,. ... 54] 0.31 [.27,. 35] 0.36 [.31,. 41] 0.29 [.25, 33]a3 Guess depth 3, item detected 0.24 [.2,.

3 May 2005: 1.9 RAM memories. Figure 24 shows a random access memory or RAM. ... A single-throw switch must bede-bounced using a timer. 24. A. B.