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17 Aug 2005: 12 13 14 15 16 17 18. 34 24 23 26 25 28 27. ... 78 46 58 36 15 24 13 2 1 2 2 2 2 1 2.

5 Jul 2005: II | 27/170 48/146. III | 11/52 29/64. Unclassified | 24/118 49/104. ... P.M.E.Altham 24. Null deviance: 452.346 on 89 degrees of freedom. Residual deviance: 83.201 on 84 degrees of freedom.

5 Sep 2005: In other methods real-space grids with finite-difference [22, 24]or multigrid [25, 26] techniques, B-splines or blip functions [27], localised spherical-waves [28],numerical atomic orbitals [29, 30, ... Rev. B 66 035119[24] Hernández E, Gillan M J and

2 Sep 2005: 2b/&K2< 75-/24: 7/Yuj:&N,1$dw. &N,.(mj< O:&N,.()YO 6=0C0 2:[àj/&N,1$i()2 z E<,fTf2bLX,f|#&U24LË,.2bB,,10 &,X[ J ,1>$jF< ... 2b/&K2b( J ,b C$l,5T.()2$'Z G Lj/&)( J =5-B,4Ú.p!Ù =/TfT5,.&N&V.w. kbw+ 24<gv$l,<L21-B,@,B:(m$Zhd$'24LÏO

9 Aug 2005: 4$6/3!A@. 0 3. # = %BA : 7 # =13 ' '(7(?$ 24= / '>3. - ... 8 : 7>=@? 24= / '>3! "$#&% '. ) L " 78!

9 Nov 2005: At the other end of the spectrum: the Microsoft system 24. • ... IR engine4. Improvement: Expected answer type filter (24% improvement). • No full-fledged named entity recognition.

30 Jun 2005: Green [25].The method is still paying dividends, cf. [3, 24]. Let be an arbitrary smooth 2-form. ... Math. 246, Amer. Math. Soc., Providence, RI, 1999. [24] N. Gouda, A theorem of E.

8 Aug 2005: Technical ReportNumber 642. Computer Laboratory. UCAM-CL-TR-642ISSN 1476-2986. First-class relationships inan object-oriented language. Gavin Bierman, Alisdair Wren. August 2005. 15 JJ Thomson Avenue. Cambridge CB3 0FD. United Kingdom. phone 44 1223

4 Jan 2005: Technical ReportNumber 612. Computer Laboratory. UCAM-CL-TR-612ISSN 1476-2986. Location privacy inubiquitous computing. Alastair R. Beresford. January 2005. 15 JJ Thomson Avenue. Cambridge CB3 0FD. United Kingdom. phone 44 1223 763500.

14 Dec 2005: PRk,2(). 1 24. 2. π. k 3k. 2=. 36. 2π. k, thus. ... Mathematics of Computation, Vol. 24, No.109, (1970), 155–158. [5] W. Light.

15 Sep 2005: 11100 0 0000000001 0 22: A1S A+=m[1] Add in the address11001 0 0000000000 1 23: L0L ABC<<=1 Shift to correct position11100 0 0000000000 0 24: A0S ... placed in m[52]10100 0 0000000000 0 43:! S data 20<<12 Space character11000 0 0000000000 0 44: &S data 24

16 Sep 2005: Pattern Recognition Letters, 24:757–777, 2003. [8] A. H. Gee, N. E. ... Ultrasound in Medicine & Biology, 24(6):855–869, 1998. [18] F. Rousseau, P.

20 Jan 2005: System BusSystem Bus. Copyright 2001 Hewlett-Packard Company. IntelDeveloper. ForumFall 2001. Page 24“Itanium is a trademark or registered trademark of Intel Corporation.

20 Jan 2005: System BusSystem Bus. Copyright 2001 Hewlett-Packard Company. IntelDeveloper. ForumFall 2001. Page 24“Itanium is a trademark or registered trademark of Intel Corporation.

1 Dec 2005: v1(c) =. 24 1c4. 35 ; v2(c) =24 16c. 35 ; v3(c) =24 01c. ... and the matrix P. A =. 24 2 0 10 4 01 0 2.

21 Dec 2005: related method of Riklin-Raviv and Shashua [24]. On the other hand, the 3D mor-. ... mateµ̂(Di) is given by the following expression:. µ̂(Di) =. j. αjG(Di; µj, σj), (24).

29 Mar 2005: 0:00-3:003:00-6:006:00-9:00. 9:00-12:0012:00-15:0015:00-18:0018:00-21:0021:00-24:00. 1e-04. 0.001. ... 0:00-3:003:00-6:006:00-9:00. 9:00-12:0012:00-15:0015:00-18:0018:00-21:0021:00-24:00. Figure 7: Distribution of

20 Oct 2005: Text Example (MUC-5) 8. <DOC><DOCNO> 0592 </DOCNO><DD> NOVEMBER 24, 1989, FRIDAY </DD><SO>Copyright (c) 1989 Jiji Press Ltd.;</SO><TXT>BRIDGESTONE SPORTS CO. ... Black? Mikheev et al – After Step 2 (Partial Match) 24.

19 Oct 2005: J 2.9e10 5.6e9 24.50 23.00 25%. H 3.0e10 5.8e9 24.53 23.24 30%. ... WFCAM e-/s 24.4 24.3 24.6 24.9 24.2. UFTI e-/s – – 24.5 24.7 24.2.

8 Aug 2005: 01. 20. 24. 2.5. 2. 1.5. 1. 0.5. 0. 0.5. 1. ... In Proc. IEEE European Conference onComputer Vision, pages 3–19, 2002. [24] G.

9 Aug 2005: 73&)24!""K!{¢ I1[TS[Ma_XJ&:a[L5U£ [M3[TOL(¤O,Ls¥UIUL51Uc5=)0F0324!95c = c<-Cj,j,j. ... L5t$U3Ï[L$b,Ã=¿)71>'24<!'<;/"642B'0324),!"csjj&$. s"03)w!>Æ;24-),646B8% Ð!<24!$03<?71624!8732B!03!

15 Sep 2005: Martin Richards 24 Seminar 10/Dec/97. Coins. s=0. WsZs =. 1. (1 Z)(1 Z2)(1 Z5)(1 Z10)(1 Z20)(1 Z50).

6 May 2005: informal discussion in Cambridgeon 24 March 2005 to formulate apolicy that would be acceptableto the majority of Quaternaryworkers.

15 Feb 2005: 18.5. 19. 19.5. 20. mea. n D. ER. on. all. 24 d. ... RT-04f RT-04f RT-04f 23.86 24.12† Official evaluation submission. • New segmenter and clusterer resulted in 14% absolute drop in primary DER. •

15 Aug 2005: a classical Runge–Kutta method, thus obtaining the so-called Runge–Kutta–Munthe-. Kaas (RKMK) class of schemes [24, 17]. ... Matrix Anal. Appl. 15 (1994), pp. 881-902. [24] H. Munthe-Kaas, High order Runge–Kutta methods on manifolds, Appl.

19 Sep 2005: 3.24). Posing the expansion η̂ = η̂0 ǫη̂1. it follows at leading order in ǫ that. ... with the boundary condition (3.24) reducing to η̂ = 0 at y = 0,L.

15 Sep 2005: 19. 3 The Design of Cintcode 23. 3.0.1 Global Variables. 24. ... 3.0.2 Composite Instructions. 24. 3.0.3 Relative Addressing. 24. 3.1 The Cintcode Instruction Set.

4 Oct 2005: 9. 3. 1. 6 4. 17. 3. 12. 24 7. 7. ... 9. 3. 1. 6 4. 17. 3. 12. 24. 12. 7.

5 Apr 2005: 14 Rubin149 07 24 14.40 -00 33 04.1 14.124 14.145 14.206 689. ... x RU149D 07 24 15.36 -00 32 47.9 11.435 11.445 11.469 689 syn.

9 Aug 2005: #"$%&'(),""%-'"/.#-01('/-"2(3 4/0"5('65"879('%%(;:1'5<>=?@;ACBED #FD.

9 Aug 2005: 9 24 r24@&:$"fc!eC<<c (. %=. (.r2>< (5"< ; "9.( 0=& (!"f"5.-&86. (%= ... 7' n" (."#"<$ "< g" < (| &!ihj ( (!"|.$: ". E. "|c% } :=p &86 #.<2>.c"< # /.".)6 ><$ n"<$ 24!m (eY2K (12>< / "<$.

15 Feb 2005: 0.16 0.18 0.2 0.22 0.24 0.2612. 14. 16. 18. 20. 22. ... Cambridge UniversityEngineering Department. RT04 EARS workshop 24. Recent Developments at Cambridge in Broadcast News Transcription.

18 Jan 2005: E[. (J†δ)(J†δ)T]. = J†E[. δδT]. J†T. = (J T J)1 (24). ... 23). Analogously to Eq. (24), imagelocations are assumed corrupted by independent Gaussiannoise with σ = 1 pixel.

5 Apr 2005: 14 Rubin149 07 24 14.40 -00 33 04.1 14.124 14.145 14.206 689. ... x RU149D 07 24 15.36 -00 32 47.9 11.435 11.445 11.469 689 syn.

8 Aug 2005: Both, centretemplateandmarginalizedtemplateshow betterclassificationperfor-mancethanthe trainedclassifier, in particular in the high detection range.At de-tectionratesof 0.99 thefalsepositive ratefor thecentretemplateis 0.24, wherasitis 0.64for

5 Jul 2005: Rigorous Specification and Conformance TestingTechniques for Network Protocols, as applied to TCP, UDP,. and Sockets. Steve Bishop Matthew Fairbairn Michael Norrish†Peter Sewell Michael Smith Keith Wansbrough. University of Cambridge Computer

6 Dec 2005: than a /24. I shall have rather more to say about reverse DNS in Section 3.5.4, since. ... mechanisms for themselves. 24. The detailed rules for handling the various states and user preferences are set out.

6 Jun 2005: ii) Use the regression equation to predict the weight of an 18 to 24 year-old male who is 67 inches tall. ... iii) Use the above regression equation to predict the weight of an 18 to 24 year-old male who is 60 inches tall.

13 Jan 2005: lateral segmentation should help• Many optimisation issues! • Lateral segmentation: 1cm2 matched to RMoliere• Longitudinal segmentation: 40 layers (24 X0, 0.9λhad)• Achieves Good Energy Resolution:. ... ILCD Paris 13/1/2005 Mark Thomson 24.

9 Aug 2005: Z l <HlV6Cqh9<FH8:<98hdp. s. hZ<.hZ -;o8CEk%<o>F<H9<HieNPFWCq:u=6YH9<eNd+ s. s l <HdEeNHC 24-&V6CqCE:u7H18:<98hdp. ... d o FWCNo PeC:<9>=iHiX XeOCE:<98dpkoWCNeh9;e<HdEeNHC 24-&V6CqCE:u7 k6:e e4HCO9LwoWCE,:eN o89 oW=8HiXw.

16 Aug 2005: 1 Bricklaying 2.24. 2 Masonry 2.24. 3 Carpentry 2.24. 4 Slater, tiler, thatcher 2.24. ... 5 Plasterer, painter, decorator 2.24. 6 Plumber, glazier 2.24. 7 Construction, public works, etc.

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2 Oct 2005: 151820. 22. 160.047. 160047. 23. 164.142. 164142. 24. 170.119. 170119. 25. ... 107736. 23. 115.289. 115289. 111184. 24. 116.609. 116609. 116609. 25. 117.338.

26 Jul 2005: LT. 0.500E-01 CONF 1 E = 40.20 ( 0.043) rejected by energy CONF 1 E = 24.24 ( 0.123) is unique and stored as structure 12 CONF 1 E = ... 0.102) rejected by structure 16 CONF 1 E = -13.19 ( 0.631) rejected by starting geometry CONF 1 E = 24.24 ( 0.100)

16 Feb 2005: Lecture 24. Example Sheets:. .

3 Feb 2005: Accretion Discs Mathematical Tripos, Part III. Dr G. I. Ogilvie Lent Term 2005. Linear case. In the linear case, the general solution may be found as a linear superposition of elemen-. tary solutions. One may look for elementary solutions in which

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2 May 2005: Although there have been recent efforts to design more realistic models [24], the level of detail is insufficient for our feasibility evaluation. ... The results are shown in Figures 17 to 24. Our first observation is that the instantaneous variation in

30 Nov 2005: 24. Atsushi Igarashi, Benjamin Pierce, and Philip Wadler. Featherweight Java: A min-imal core calculus for Java and GJ. ... ACM Trans.Program. Lang. Syst., 24(3):193–216, 2002. 33. Wolfgang Naraschewski and Tobias Nipkow.