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3 May 2005: 1.9 RAM memories. Figure 24 shows a random access memory or RAM. ... A single-throw switch must bede-bounced using a timer. 24. A. B.

12 Apr 2005: 302k 9k+ 16.0 13.9 24.8 –MLE 415k 9k+ 16.0 13.5 24.3 –. 398k 12k+ 16.1 13.6 24.5 –. 302k 9k+ 13.2 11.2 ... dev04 eval03 dev04f. MLEMPron 16.0 13.6 24.5SPron 15.6 13.5 24.2. MPEMPron 12.9 11.1 19.1SPron 12.7 10.8 18.8.

28 Mar 2005: At least it has been adequateto obtain some results quite quickly for the main precisionsthat interest us, p {24, 53, 63, 113}. ... 20 19.45 7.90 1.525 24 32 5 13. 30 29.45 10.39 1.535 26 33 52 7 17.

27 Jan 2005: Thenumber 1.234 should be rounded to 1.23 and 1.238 should be rounded to 1.24. ... However, p = 24 because a hidden bit is used. Zero is represented by an exponent ofemin1 and a significand of all zeros.

5 Sep 2005: 5.1 Terms and types. Thetypes, expressions, andtermsof the PCF language are defined on Slide 24. ... Slide 24. The intended meaning of the various syntactic forms is as follows. •

12 Apr 2005: S1 6K (28)0. 34.1 26.0 30.2 26.4S4 9K (36). (ML)33.0 24.8 29.0 25.3. ... 32.3 22.9 27.8pMPEMPE 35.1 26.0 30.7 33.2 24.1 28.8 32.9 23.6 28.4.

26 Mar 2005: 12.5. 13. 13.5. 14. 14.5. 15. SID Threshold. Dev. (24. sh. ... 11. 11.5. 12. 12.5. 13. SID Threshold. Eva. l (24. sh.

9 Nov 2005: Very high compression makes this task harder• Results:. Feature Individual CumulativeCue Phrases 33% 33%Location 29% 42%Sentence Length 24% 44%tfidf 20% 42%Capitalization tfidf 20% 42%Baseline 24%. ... Strategies for summary evaluation 24. 1.

17 Feb 2005: The tax-onomy lists 412 mental state concepts, each assigned to one (and only one)of 24 mental state classes. ... The 24 classes were chosen such that the seman-tic distinctiveness of the emotion concepts within one class is preserved.

5 Sep 2005: Phys. Commun. 162 24[20] Pask J E and Sterne P A 2005 Modelling Simul. ... Rev. Lett. 93 176403[24] Mostofi A A, Skylaris C-K, Haynes P D and Payne M C 2002 Comput.

18 Mar 2005: 449 Checker output. 4910 Checker output: the symbolic transition derived for Step 24.

22 Jul 2005: 0 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 320 10 20 300. ... 0 4 8 12 16 20 24 280. 0.1. 0.2. 0.3.

7 Feb 2005: Mathematical Tripos Part IILent 2005. Professor A. Iserles. Numerical Analysis – Lecture 121. Methods 3.25A generalν-stageRunge–Kutta methodis. kl = f. . tn clh, yn h. ν. j=1. al,j kj. .  where. ν. j=1. al,j = cl, l = 1, 2,. ,

15 Jun 2005: α0. 24 1(1)(2). 35 = α0w = nXi=1. αsvmi yiG1(oi; ) (22). ... O; )). 375 (24)This allowsβ to be set using maximum margin training. Howeverempirically settingβ has a number of advantages.

12 Nov 2005: Find a monic polynomial over Z of degree 4 whoseGalois group is V = {e, (12)(34), (13)(24), (14)(23)}.(ii) Let f Z[X] be monic and separable of degree

16 Mar 2005: H. Berman. Engineering a freehand 3Dultrasound system. Pattern Recognition Letters, 24(4–5):757–777, 2003. ... Ultrasoundin Medicine and Biology, 24(9):1243–1270, 1998. [22] R. W. Prager, A.

9 Sep 2005: ophthalmologist preferably within 24 hours of the injury occurring. The injured person must not drive. ... wavelength, power/energy per pulse and pulse duration. Addenbrookes Hospital: Accident and Emergency Department open 24 hours a day.

4 Mar 2005: Implementation 5.24 It is quite usual to solvehyperbolic PDEs (advection equation, wave equation,Schr̈odinger equation, Euler equations of invicid compressibleflow. )

27 Feb 2005: Technical ReportNumber 616. Computer Laboratory. UCAM-CL-TR-616ISSN 1476-2986. Dictionary characteristics incross-language information retrieval. Donnla Nic Gearailt. February 2005. 15 JJ Thomson Avenue. Cambridge CB3 0FD. United Kingdom. phone 44

3 May 2005: 22. 23. 24. 25. 26. 27. 28. 29. 30. 31. 32. ... 10. 9. 44. 45. 46. 24. 26. 39. 25. 21. 22.

13 Oct 2005: Thenumber 1.234 should be rounded to 1.23 and 1.238 should be rounded to 1.24. ... However, p = 24 because a hidden bit is used. Zero is represented by an exponent ofemin 1 and a significand of all zeros.

26 Jul 2005: 24.98 ( 0.344) is unique and stored as structure 10 CONF 1 E = -8.47 ( 0.974) rejected by energy CONF 1 E = -8.35 ( 1.043) rejected by energy ... LT. 0.500E-01 CONF 1 E = -27.89 ( 0.045) is unique and stored as structure 11 CONF 1 E = -24.94 ( 0.107) is

24 Nov 2005: Page last updated on 24-Nov-2005 at 11:09 by Jon Crowcroft.

13 Oct 2005: Thenumber 1.234 should be rounded to 1.23 and 1.238 should be rounded to 1.24. ... However, p = 24 because a hidden bit is used. Zero is represented by an exponent ofemin 1 and a significand of all zeros.

26 Jul 2005: LT. 0.500E-01 CONF 1 E = 62.24 ( 0.044) replaces structure 31 Minimization converged; gradient = 0.360E-01. ... LT. 0.500E-01 CONF 1 E = 62.24 ( 0.032) replaces structure 31 Minimization converged; gradient = 0.439E-01.

26 Jul 2005: 3 CONF 1 E = -201.24 ( 0.607) is unique and stored as structure 4 Minimization converged; gradient = 0.398E-01. ... 0.161) replaces structure 24 CONF 1 E = -221.33 ( 0.425) rejected by starting geometry Minimization converged; gradient = 0.456E-01.

13 Oct 2005: Thenumber 1.234 should be rounded to 1.23 and 1.238 should be rounded to 1.24. ... However, p = 24 because a hidden bit is used. Zero is represented by an exponent ofemin 1 and a significand of all zeros.

26 Jul 2005: LT. 0.500E-01 CONF 1 E = 154.00 ( 0.049) rejected by structure 24 Minimization converged; gradient = 0.380E-01. ... LT. 0.500E-01 CONF 1 E = 154.00 ( 0.028) rejected by structure 24 Minimization converged; gradient = 0.469E-01.

24 Feb 2005: Page last updated on 24-Feb-2005 at 12:06 by Keir Fraser.

17 Feb 2005: Here are other dynamic brightness illusions. (24 Feb 2005): Exercises 13 and 14.

13 Oct 2005: Thenumber 1.234 should be rounded to 1.23 and 1.238 should be rounded to 1.24. ... However, p = 24 because a hidden bit is used. Zero is represented by an exponent ofemin 1 and a significand of all zeros.

9 Aug 2005: #"$ %&%. ')(),.-0/,132145467 8:9;(1,<>=@? A3B:CED5FHGIFKJELMDNFHDPOQBMD5RSUTVLWBMCEDXRDPY0LMDPDZT5S[ TQ]BMT0LT5S_aCEGcbdTeFfTVJECQg. GdOh bcD5iBMLMGIPjkb)j5OlR h bcDN]BML:TVOEGI h OEYVGdOEDPDPL:GcOEY. j5BB:CEDm

23 Aug 2005: Sutcliffe, A.J. 1988 Report of the Geologists' Association Field Meeting in north-east Essex, May 22-24, 1987. ... Quaternary Newsletter 56, 23-24. 37. Gibbard, P.L., Whiteman, C.A. & Bridgland, D.R.

7 Feb 2005: y0, n = 0, 1, 2,. 24. The following four-stage Runge–Kutta method has order four,.

9 Aug 2005: Figure 1: Variation in error at each of 24 network outputs over the course of the sentence “clear windows”. ... Figure 4 shows the MSE for both the (5,32,24) network trained on the original data and the.

28 Sep 2005: 12 13 14 15 16 17 18. 34 24 23 26 25 28 27. ... 78 46 58 36 15 24 13 2 1 2 2 2 2 1 2.

15 Sep 2005: REPEAT. // End of Model checking algorithm. 24 3 A µ-CALCULUS MODEL CHECKER. / ... edge(2,22,23); edge(2,23,25); edge(2,25,27); edge(2,27,29)edge(2,25,16) // loop back to 16. edge(2,22,24);

26 Jul 2005: LT. 0.500E-01 CONF 1 E = 129.82 ( 0.048) rejected by structure 24 Minimization converged; gradient = 0.481E-01. ... LT. 0.500E-01 CONF 1 E = 129.82 ( 0.027) replaces structure 24 Minimization converged; gradient = 0.438E-01.

26 Jul 2005: 0.156) is unique and stored as structure 24 Minimization converged; gradient = 0.375E-01. ... LT. 0.500E-01 CONF 1 E = 6.97 ( 0.034) rejected by structure 24 Minimization converged; gradient = 0.316E-01.

26 Jul 2005: LT. 0.500E-01 CONF 1 E = 98.24 ( 0.049) rejected by structure 13 Minimization converged; gradient = 0.426E-01. ... LT. 0.500E-01 CONF 1 E = 95.28 ( 0.034) replaces structure 24 Minimization converged; gradient = 0.315E-01.

24 May 2005: In addition to this, see the revision questions in Varian's textbook, chapters 1-6, 14-17, 24-25, 27-28 and 32-36, and the problems in its companion volume

26 Jul 2005: 1.221) rejected by energy CONF 1 E = -458.36 ( 0.436) rejected by energy CONF 1 E = -425.24 ( 0.931) rejected by energy CONF 1 E = -394.07 ( ... 1 E = -538.24 ( 1.494) is unique and stored as structure 13 CONF 1 E = -484.74 ( 0.352) rejected by energy

26 Jul 2005: LT. 0.500E-01 CONF 1 E = 144.45 ( 0.033) rejected by structure 24 Minimization converged; gradient = 0.458E-01. ... LT. 0.500E-01 CONF 1 E = 144.45 ( 0.028) replaces structure 24 Minimization converged; gradient = 0.346E-01.

23 Nov 2005: 24 November. Peter Challenor. (Southampton). Wave climate from space -- from Geosat to Hurricane Katrina.

9 Aug 2005: #"$%&')(,-.%%&( 0/-#1""324%5/246"78&9:5. ;<8<'7>=@?9A@BA@BDCE<8F@<'8=HGIBDJK=B&L>MNMNO>PQ'/I JRI =BSA@BDCT8=G>=UVI ONJW(XY=ZL@Q. "M>L[AXYU]M>BDU=>_8B?IBDMNM>XaIBD?HQ.BI bDM>XcJ4I Ued=>_#'A@]G[XaI C?@M. ;'&'f2#PI JL[A@L[M>XCMNJKO>XgI,G[MNJABDMNhA@i? @

26 Mar 2005: 22. 1 (mod 23) by Fermat. 21 -2 (mod 23) and 2.12 = 24 1 (mod 23) so 21.11 (-2).(-12) 1 (mod 23).

26 Jul 2005: LT. 0.500E-01 CONF 1 E = 84.44 ( 0.041) replaces structure 24 Minimization converged; gradient = 0.478E-01. ... E = 73.24 ( 0.170) rejected by structure 36 Minimization converged; gradient = 0.413E-01.

26 Jul 2005: LT. 0.500E-01 CONF 1 E = -209.88 ( 0.036) is unique and stored as structure 24 CONF 1 E = -225.45 ( 0.105) rejected by structure 15 CONF 1 ... LT. 0.500E-01 CONF 1 E = -230.49 ( 0.049) replaces structure 6 CONF 1 E = -227.24 ( 0.164) replaces structure

22 Mar 2005: NaI  2853.012 6.77e-4 5.54e5  M03. NaI  2852.811 1.35e-3 5.54e5  M03. MgI  2852.963108 1.830000  5.000e8 24.3050 M03g w:MN

26 Jul 2005: LT. 0.500E-01 CONF 1 E = 36.78 ( 0.041) rejected by energy CONF 1 E = 20.86 ( 0.059) rejected by energy CONF 1 E = 28.24 ( 0.537) ... 167) rejected by energy CONF 1 E = 10.20 ( 0.425) is unique and stored as structure 24 Minimization converged; gradient =