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15 Sep 2004: 0.79 0.08 -0.83 0.95 N 0.0 0.0 0.0 0.0e00 0.00 -23.31 0 -22.03 1 -23.90 -3 -24.75 1 ... wfc1 02 55 43.74 00 10 26.7 5.6 5.4 -1.5 1.6e00 0.62 -23.31 0 -22.03 0 -23.90 0 -24.75 0

11 Oct 2004: InLeicester he developed pioneeringMasters and PhD programmes byDistance Learning, and the Schoolwas awarded the maximum scoreof 24/24 by the Quality AssuranceAgency in 2001. ... November 24.Royal Holoway, London Quaternary Lectures, November

13 Dec 2004: 16, -10.11, -64.89, g, 4.81, a0620-00 g , 6.38, -0.31, -6.49, g, 2.15, IRAS105652448 , 10.99, 24.58, 64.73, g, 2.02, NGC3665Group ... g , 11.42, 38.80, 68.52, g, 2.03, wfc1202-1 z , 12.09, -7.34, 53.76, g, 1.82, IRAS13349 , 13.62, 24.42, 79.29, g,

13 Dec 2004: 19.93, -33.95, i, 2.41, NGC2023 , 5.70, -2.24, -16.46, i, 1.83, NGC2341 , 7.16, 20.63, 13.05, i, 1.60, 3C192 U , 8.10, ... 24.86, 26.68, i, 1.65, YZCNC , 8.19, 28.18, 28.86, i, 1.80, lynx3anw r , 8.82, 44.89, 39.20, i, 2.00, 3c223 g ,

13 Dec 2004: 16, -10.11, -64.89, r, 3.76, mbm12 , 2.95, 19.93, -33.95, r, 3.80, lb227 r , 4.16, 17.17, -24.65, r, 1.77, ms0419.3 ... 2.39, NGC3665Group g , 11.42, 38.80, 68.52, r, 1.76, IRAS13349 , 13.62, 24.42, 79.29, r, 1.83, rxj1354.3-0222 r , 13.91, -2.33,

21 Oct 2004: 10 Maximal ideals 23. 11 The Gelfand representation 24. 1. 12 Finding the Gelfand representation 26. ... Exercise 24. (i) Show that the set l of bounded sequences over F (withF = R or F = C).

23 Apr 2004: 6. 61.0. 22h27m41.69s. -5d14m12.3s. -49.39. 0.4. 1.5. 3.8. 1.0017.24. 0.792.27. 0.050.16.

7 Jan 2004: 9.990 0.019 0.056 -9.990 0.019 r 11 G133-69Pos_1 01 04 24.0 -06 24 0.0 -69.04 9.99 0.03 0.01 ... 1 35 23 12.0 -24.88 0.06 0.04 0.02 0.01 0.01 0.082 0.036 -0.156 -0.060 0.036 r 26 SDS-2

9 Mar 2004: 6.3 6.3 24.3 5.89 1.00 3.86 9.6 6.1 3.8 0.7417 6.3 6.3 24.3 10.71 1.00 ... 86 9.6 8.2 5.2 0.8118 6.3 6.3 24.3 20.37 1.00 3.86 9.6 11.3 7.1 0.8919 13.2

5 Oct 2004: Exercise 24 If U is an open set in C show that there is a complete metricd on the space A(U) of analytic functions f : U C such that if ... 24. 9 L(1,χ) is not zero. Our first steps are easy.