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5 Oct 2019: worldconsider Part III to be ‘adequate preparation for direct entry to doctoralstudy’15. ... For many countries, these form part ofthe visa requirements which the university cannot alter.

4 Jul 2024: 122. (doi: 10.2307/3215269). Scheduling jobs by stochastic processing requirements on parallel machines to minimize makespan or flowtime.

4 Jul 2024: 304. (doi: 10.1214/aoap/1042765670). Separating Milliken-Taylor systems with negative, entries. N Hindman, I Leader, D Strauss. –

4 Feb 2008: By considering a suitable map from thetriangle T = {x R3 : x1, x2, x3 0, x1 x2 x3 = 1} into itself, prove that A has an eigenvectorwith positive entries. ... someτ 0, and for each x D, the requirement that this point belongs to D determines uniquely anon

30 Oct 2011: By considering a suitable map from thetriangle T = {x R3 : x1, x2, x3 0, x1 x2 x3 = 1} into itself, prove that A has an eigenvectorwith positive entries. ... someτ 0, and for each x D, the requirement that this point belongs to D determines uniquely anon

22 Jan 2009: By considering a suitable map from thetriangle T = {x R3 : x1, x2, x3 0, x1 x2 x3 = 1} into itself, prove that A has an eigenvectorwith positive entries. ... someτ 0, and for each x D, the requirement that this point belongs to D determines uniquely anon

19 Oct 2010: By considering a suitable map from thetriangle T = {x R3 : x1, x2, x3 0, x1 x2 x3 = 1} into itself, prove that A has an eigenvectorwith positive entries. ... someτ 0, and for each x D, the requirement that this point belongs to D determines uniquely anon

21 Oct 2009: By considering a suitable map from thetriangle T = {x R3 : x1, x2, x3 0, x1 x2 x3 = 1} into itself, prove that A has an eigenvectorwith positive entries. ... someτ 0, and for each x D, the requirement that this point belongs to D determines uniquely anon

11 Jun 2013: All application for undergraduate entry have to be in by a fixed date some-time in the middle of October for entry in the following October. ... 13 Older candidates. There is no upper age limit for entry to Cambridge.

5 Jun 2020: Γ.G/θÅ =π{F̂ G. P F̂ /.PG/},where the k k matrix Γ.G/ has entries Γ.G/ij =π{GiGj. ... the matrix k.I A/1, where A has entries Aij = Qij =Qii, 1 i = j k, Aii = 0 for all i,and I A is always invertible.Proof.