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4 Mar 2005: t3). (5.16). Thus,etBetC = et(BC) t 0 only if B andC commute.[Note: It is trivial to prove that commutativityis sufficient, not just necessary.]The good news is, however,

21 Feb 2005: to the grid) pass unnoticed!Bad news:For |θ|, |ψ| = O. (. ... small attenuation already familiar from the analysis of Gauss–Seidel.Good news:Consider just thelarge frequencies.Then.

7 Feb 2005: . . You should find that the(2, 3) element of the new matrix isO(. ... ε3). and that the new matrix has exactly thesame trace asA.

7 Feb 2005: Definition 3.10 (Multistep methods)It is often useful to use past solution values in computing a new value.Thus, assuming thatyn, yn1,. ,

31 Jan 2005: adjacent columns of a matrix, thetotal number of nonzero elements in the new combination of rows or columns is at most five.

19 Jan 2005: It follows from the symmetry ofAand the new assertion(2) that the proof is complete.

25 Jan 2005: The reason for the new step2 is thatf (λ) = 0 implies thatx(k) satisfiesAx(k) = (λ s(k))x(k).

15 Aug 2005: conveniently modified version of the Magnus expansion to construct a new class of. ... Here new Lie group solvers up to order four for (2) are presented.

14 Sep 2005: ωs1. ). Like the Filon-type method, this new method uses interior points as. ... A[. ddx. fg′. ]. Hence we have derived a new approximation of I[f], namely QA[f] 1iωQ.

23 Nov 2005: Even then the singularity of h. (with the new definition of f̃) at ξ is not removable.