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31 Jan 2024: i) if f ' g then π0(f) = π0(g),. (ii) for maps A h B k C we have π0(k h) = π0(k) π0(h),. ... It satisfies. (i) π1(f) is a group homomorphism,. (ii) if f is based homotopic to f ′ then π1(f) = π1(f ′),. (iii) for based maps (A,a) h (B,b)

14 Sep 2023: If χ: A B is an algebra homomorphismthen there is b B such that χ(x) = bxb1 for all x A. ... OF kD. We have Nrdι = NL/F by [23, Proposition 16.2(b)].

24 Oct 2023: Cnk. Since Hom(AB,C) = Hom(A,C)Hom(B,C) for abelian groups A,B, we may assumethat G is cyclic of order n, with generator n.

31 Aug 2023: 0. q(t) = Aeω02Q t cos(ωt ϕ) q(t) = (At B)eω0t q(t) = Ae. ... A0. ω. b′kSpectre de us. 35. CHAPITRE 9. RÉPONSE FRÉQUENTIELLE DE SYSTÈMES LINÉAIRES.

29 May 2024: 1 B. It follows that ω. 1 6 ω1, which is a contradiction. ... If B 6= A, thenfor any x A B, the extension (B,R) =. (B {x},R {(b,x) : b B}. )contradicts the maximality of (B,R).

31 Aug 2023: On définit B(), B(A) et B(B)de manière analogue. On a alors A = A() A(A) A(B), B = B() B(A) B(B),A() B(), A(A) ... A) et A(B) B(B), ce qui permet de construire une bijectionde A dans B.

31 Aug 2023: Alors. A, B, C sont alignés arg(caba. ) 0 [π]. IV Identités remarquables. ... Démonstration. On recherche (ω) tel que f() = , soit ω = aω b, i.e.

5 Jun 2024: Appendix A. Bounded geometry 45. Appendix B. The h-cobordism stabilisation map 48. ... Given a map i : B B′ which agrees with the underlying map of I on 0 B, let ˜BunMap0 (ξ,π; i)•the semi-simplicial subset consisting of those bundle maps