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30 Apr 2024: 37.51 = 3751 102. Eg, for positive numbers, take A1  a  A2 and B  b < B+. ... A pA2 b. =b. A pA2 b. We can estimate this as bAC , which reduces the relative error.<latexit

13 Dec 2018: there. exists p, say, such that p _-> V {P2,Pt} and b o t h ( b , , - b ) p and (be - b)p are. ... a b o v e we can suppose, for each po => pl, that (b - b l ) p l = 0, b y replacing each b.

13 Dec 2018: erf. [. A. B. AX. B. )]. B. AX. (. erf. ). A. AX. (. erf. [. A. B. AX. B. )]. ... 1. (. t. y. D. x. Q. -. =. where A=a/(2((Kt)), B = b//(2((Kt)) and X = x/a.

6 Mar 2013: b. Thus two linearly independent solutions of Legendre’s equation can be written, in the casewhen m is not an integer (so that the exponents at the origin do not differ ... a(a 1)b(b 1). c(c 1). z2. 2! 2.

19 Oct 2013: " # # $ $ $ $&% $ ' ( '' ' '' ' '' ' ),.-'' ' ( '' ' ( '' ' '( ' / / ' '0 $ $ $ $ 1/ '32 '"4. 11 576 ' ' ' '98. # # : # # ; # # < = >@?BADC9A"CFEHGHIJC. > ; < ; : < =? BADC9A"CFEHGHIKC 0 $ $ $ $ ' ' ' ' / L '( / 2 M5N5PORQTSUQVSXWY[ZXS. -/ ' '0 $ $ $

30 Mar 2007: Vortex Equations:. Tvortex = 2πv2Vortex Tension:. Vortex Moduli Space. Suppose we have an Abelian vortex solution ,. We can trivially embed this in the non-Abelian theory. When. B =B?0.(. ... It has mass. ( )B = B?0. CPN1. Mkink = r|m1 m2| = 4π hφie2 =

5 Dec 2008: x µy) (x µy) = 0 , x = |a|2b |b|2a , (2x y) (a b) = λ. ... 2. (a) Show that. a (b c) = b (c a) = c (a b).

26 Jun 2024: generators of SU(3) which we take to obey. Tr(T AT B) =1. ... fact that quarks carry colour indices, which are the a, b, c, d = 1,. ,

19 Oct 2013: d T T T TV V V V V. b V VW V VX V V V V V VX VT e TgfV VX V V. ... h?h T T T TikjmlnjolEp [:q l VX VX b b VX Vc VX V r!s t.

21 Jun 2007: Vortex Moduli Space. Suppose we have an Abelian vortex solution ,. We can trivially embed this in the non-Abelian theory. B =B?0.(. ... Vortices with Masses. B = B?0.(0. ( ((q = q?v v.