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23 May 2024: b B(OF ) whose discriminant is strongly (resp. weakly) divisible by I 2. ... 2. Let b B(Op) be an element with discriminant weakly divisible by p2.

29 Oct 2021: finitely generated A-module, then Supp(B A M) =. (f)1(Supp(M)). [Note: You may find useful the identity on tensor products (M A B) B C = M A C ... given an A-module M,an A-algebra B and a B-algebra C.].

14 Jul 2024: The last rule in the proof of A B C can only be a -R. ... B. So then theboolean ring B′ corresponding to B believes the ring formula φ′ corresponding.

12 Sep 2013: That is b x = θ(b)x for b B+ and x Kθ. ... We can compute that for b B+,log b pn1b+ acts by log θ(b) pR.

8 Dec 2005: say with active coordinate set I, such. that for all a [m]n and all b, b′ L{L+}, we have c(a, b) = c(a, b′) = c′(a),say. ... ii) A B U if and only if A U or B U;.

4 Feb 2021: BBB = {x : (B B)(x B)}. (a) Let B P() and C P(). ... B C) (BB. B) (CC. C). (b) This part seems to have caused problems for some.

30 Aug 2022: I was asleep at the wheel. Should read(iv) If a a′ and b b′ then a b a′ b′ mod n.Page 124 Proof of Lemma 4.3.10 (ii), ... which simplifies to. b(3 b) (b 1)2c > 1. Page 254 Replace first part of Exercise 9.2.3 as followsExercise 9.2.3 (i) Show that

26 Apr 2021: This means we have proved. GCD(b Fn4 a Fn3, b Fn2 a Fn1) = GCD(a b, b). ... But of course GCD(a b, b) = GCD(a, b) so we get.

28 Nov 2012: Forexample if a,b C and x,y,z V , then. (x,ay bz) =1. ... Then 〈Pa,Pb〉 = (a,b) for a,b V. So for each g G.

11 Jan 2024: Show that the linear map A : R2 R2 peserves theequivalence relation (a,b) (a′,b′) (aa′,bb′) Z2, and so induces a continuous map fAfrom the torus T to itself.