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15 Oct 2021: Consider the sequence of distributions. uM =. Mm=M. D|m|δm. Let φ D () be any test function. ... u1φ = (u1? φ̃)(0) = (u2? φ̃)(0) = u2φ. for any test function φ, thus u1 = u2.

5 Jun 2020: of the spike count in the data (as quantified by the Fano factor).This conclusion is rigorously justified with a t-test with a p-value of 5 104. ... Fanofactors and the percentage drop is zero, and the test statisticis t = r.

6 Feb 2021: Show also that. n=1(1)n1andiverges. [This shows that, in the alternating series test, it is essential that the moduliof the terms decrease as n increases.]. ... sequence. Prove that. j=1 ajbj converges. Deduce the alternating series test. Does the series.

2 Oct 2023: From this limiting result: (i) derive a test for the hypothesis H0 : θ = θ0 vs. ... For all these models, derive explicit expressions for the likelihood ratio test statistic ofa simple hypothesis test of H0 : θ = θ0, θ0 Θ, vs.

23 Feb 2015: SXX/(n1)}1/2. Determine the distribution of T under H0, and hence. determine the size α likelihood ratio test. ... size α likelihood ratio test of equality of means rejects H0 if.

24 Jan 2012: bndivergent. 9. (Abel’s test.) Let an and bn be two sequences and let Sn =n. ... Deduce the alternating series test. Does the series. n=1cos(n). nconverge or diverge?

21 Jan 2011: bndivergent. 9. (Abel’s test.) Let an and bn be two sequences and let Sn =n. ... Deduce the alternating series test. Does the series. n=1cos(n). n converge or diverge?

8 Oct 2007: Hint: Use the Weierstrass M-test from Analysis II to show that these series are locallyuniformly convergent.].

11 Oct 2019: 10. This question is about understanding what can happen to the F-test when the expected value ofthe response is not necessarily linear in β. ... e) Let Z σ2χ2np. Show thatZ ‖(I P)Y‖2. Conclude that the size of the test mentioned at the beginning

15 Oct 2021: i=0. |ai|. converges. You may have studied various criteria for a series to converge (ratio test, roottest, comparison test. ).