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8 Jul 2009: σtotn = 1Ca. κn, on ΓM(t). (24). Since there is no fixed boundary in this problem, the purely.Lagrangian approach is well adapted to it. ... Non-Newtonian Fluid Mech. 110 (2–3)(2003) 77–102. [24] R.F. Liang, M.R. Mackley, Rheological

13 May 2009: Van,cn(α, β, nz) =. 0(t α)a(t β)cenφ(t) dt, (4.23). withφ(t) = zt log(t α) log(t β) (4.24). ... Iserles (DAMTP, University of Cambridge). 24. References. [1] Milton Abramowitz and Irene A.

31 Jul 2009: SZAN-IAWSKI, A. 1972 Arch. Mech. 24, 555. TANNER, R. I. 1971 J.

1 Dec 2009: 3.24). The corresponding result is the following. Theorem 2 Let f(y) be constant, then we have θ0 = 0, θ1 = ̺ and. ... θs = (s 1)̺, s 2.Proof We shall use formula (3.24) and proceed along the lines of theproof of Theorem.

23 Jul 2009: Rallison and E. J. Hinch. Without H I 1 84 1 1-24 - a9 With accurate HI 11.474 1-1.814 1-2.064 -2.224 Batchelor (1976, 1983) 1 ... pO as r / a c o , (3.24). and P-D;Vp = ikD,.P on r = 2a.

10 Jul 2009: For the same trial as in Fig. 5, this constantB is found to be20.90 and 24.29 for the large andsmall angle sides, respectively.

13 Jul 2009: Denn, J. Non-Newtonian Fluid Mech., 24 (1987). 85-96. 6 P.J. Coates, R.C.

10 Jul 2009: J. Fluid Mech. (2002), vol. 452, pp. 371–404. c 2002 Cambridge University PressDOI: 10.1017/S0022112001007017 Printed in the United Kingdom. 371. Constitutive laws in liquid-fluidized beds. By P A U L D U R U 1, M A X I M E N I C O L A S1, J O H N

23 Jul 2009: 7 2 13.3 19.7 34.0 % / a , 1.33 1.64 2.13 2-55 3.63 4.24 5. ... Even for r = 30 a 24 Yo variation from axisymmetry produces a drift in 6 from &7r to approximately.

3 Sep 2009: R1. 2r0R2. 2. R12. r0 R1 , 24. where a sign has been added to indicate the circulationof the vortex.