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17 Mar 2006: Part IID RIEMANN SURFACES (2005–2006): Revision Example Sheet. (a.g.kovalev@dpmms.cam.ac.uk). Note. The present 24-lecture course on Riemann Surfaces was first lectured in the academic

21 Feb 2006: You should justify the differentiation.). 24. Let C : [0, 1] C, t 7 exp 2πit be the unit circle that divides C into two parts D = {z C : |z| < 1}and

25 Oct 2006: A; :=JKµE@JKZ7fÞ Ó <KG 24] @ 5sGAA5O7Bj :=Jlß 1 M7p/:=8K:(Gme7:A6v@ <9f89fqR:5R8I:A; :=JA0S7@rZÈ8IsGQ8 E@J<>màDAf:A5O89yfyÆGQJI; :v7JIfBD:oÔ"Ä:Q7E@JGyysm84s57f89:Ayf(BxG5O{v7JIBC:A<

4 May 2006: 24. Let X be a compact topological space. Prove that for any topological space T the secondprojection map X T T is a closed map (i.e. ... Hard) We now prove the converse to q.24: a space X is compact if for all spaces T the secondprojection pT : X T T is

30 Oct 2006: 24) (i) Show that H(X|Y ) 0 with equality if and only if X is a function of Y.

4 May 2006: 24. Let X, Y be topological spaces. Define an equivalence relation on X Y by (x, y) (x′, y′) y = y′.

16 Feb 2006: You should justify the differentiation.). 24. Let C : [0, 1] C, t 7 exp 2πit be the unit circle that divides C into two parts D = {z C : |z| < 1}and

10 May 2006: energy level). Wojtkowski has pointed out [24, Theorem 2.4] that the dynamics of(17) reparametrized by arc-length defines a flow on SM which coincides with theisokinetic thermostat with external ... Math. Pures Appl. 79 (2000) 953–974.[24] M.P.

2 Aug 2006: Ä» %¿(!0»µ(í µ[!o!µPî X Z í ] Ú»%0!µÅÄ%!»%»! cÈÞµTÀµ{%¿a.µwÂõwÁ>µwk»%í É»kf[vµË. ØÙØ ï«ÜÝcð5ñóòÜuÝÞßpàÙ 24.5,¢>@A"CBEDP8w.5,( 2 ... Ù 24.5,/6 Ç X 6M0, ;(F7D ÃÀ6»%ÆÃÇ Ä%!»% < vÀ.Åa%¿( X

13 May 2006: Similarly the ternary cubicx3 2y3 5z3 = 0 has discriminant = 24.39.54 yet is 3-adicallyinsoluble. ... In the case n = 2, we find. c4 (α21 4α0α2 4c)2 (mod 24).We set b2 = α.