Search

Search Funnelback University

Search powered by Funnelback
11 - 17 of 17 search results for KaKaoTalk:PC53 24 / |u:www.dpmms.cam.ac.uk where 0 match all words and 17 match some words.
  1. Results that match 1 of 2 words

  2. What is the probability that a random integral quadraticform ...

    https://www.dpmms.cam.ac.uk/~taf1000/papers/isotropic.pdf
    15 Sep 2015: P(λ(M) [λ dλ). )=. 1. ZGOEn|(λ)|. ni=1. e14λ2i dλi; (24). here(λ) :=. 1i<jn. (λj λi) = det(ϕi(λj)),. where (ϕi(λj)) = (λi1j ) is a Vandermonde matrix, and
  3. 7 Aug 2015: It is known [24] that Ū(g) is a Fréchet-Stein algebra. We view Ū(g) as aquantisation of the algebra of rigid analytic functions on g in much the same
  4. Automorphy of some residually dihedral Galois representations Jack A. …

    https://www.dpmms.cam.ac.uk/~jat58/version_over_F.pdf
    3 Apr 2015: Automorphy of some residually dihedral Galois representations. Jack A. Thorne. April 3, 2015. Abstract. We establish the automorphy of some families of 2-dimensional representations of the absolute Galoisgroup of a totally real field, which do not
  5. LINEAR ALGEBRA SIMON WADSLEY Contents 1. Vector spaces 21.1. ...

    https://www.dpmms.cam.ac.uk/~sjw47/LinearAlgebra.pdf
    20 May 2015: 24 SIMON WADSLEY. Proof. (a). tr AB =. ni=1.  mj=1.
  6. LINEAR ALGEBRA SIMON WADSLEY Contents 1. Vector spaces 21.1. ...

    https://www.dpmms.cam.ac.uk/~sjw47/LinearAlgebraM15.pdf
    2 Dec 2015: mj=1. λiµjψ(ei,fj). 24 SIMON WADSLEY. Therefore if A is the matrix representing ψ with respect to (e1,.
  7. 10 Dec 2015: Level-raising and symmetric power functoriality, III. Laurent Clozel and Jack A. Thorne. December 10, 2015. Contents. 1 Introduction 11.1 Notation. 3. 2 Admissible representations of a ramified p-adic unitary group 42.1 A unitary group Hecke algebra.
  8. Department of Pure Mathematics and Mathematical StatisticsUniversity…

    https://www.dpmms.cam.ac.uk/~tkc10/CodesandCryptography/CodesandCryptography.pdf
    10 Mar 2015: For example, Hamming’scode is 1-error correcting, K = 24, N = 7 and. ... So K = 24 = 27/8 = 2N/V (7, 2) and the code is perfect.

Refine your results

Search history

Recently clicked results

Recently clicked results

Your click history is empty.

Recent searches

Recent searches

Your search history is empty.