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5 Oct 2013: J. Amer. Math. Soc., 24(1):81–124, 2011. 1.

5 Oct 2013: R. Driscoll, “Wavelet-encodedMR imaging,” Magn. Reson. Med., vol. 24, pp. 275–287, 1992.

5 Oct 2013: R. Driscoll, “Wavelet-encodedMR imaging,” Magn. Reson. Med., vol. 24, pp. 275–287, 1992.

4 Oct 2013: Xn(x) = Bn sinnπx. Lλn =. n2π2. L2. (24). Note that the first set eq. ... 24) the timeequation gives. Tn(t) = Cn exp(Dn2π2. L2t). The general solution for θ̂ (with odd initial condition θ̂(x, 0)) is thus.

4 Oct 2013: u,Av) = (Bu,v) (24). (as you can easily check using the property that (Bu)† = u†B†). ... 36) of the µn values.). 1B Methods 24. 2.5 Parseval’s identity and least square approximations.

5 Oct 2013: xm} is a grid of mequispaced points in [1, 1]. In [24] it was shown that. ... Proc. SPIE, 7535, 2010. [24] D. Coppersmith and T. Rivlin. The growth of polynomials bounded at equally spaced points.

4 Oct 2013: n2π2 1. (24). On the other hand we had in a previous example the expression constructed from homo-geneous solutions:. ... ξ. (25). Now comparing eqs (24,25) and viewing ξ as a parameter and x as the independentvariable, we see that the equivalence of

4 Oct 2013: G(x,t; ξ,τ) =H(c(t τ) |x ξ|). 2c. (24). (Note that this expression already requires tτ > 0 for G to be non-zero so we need notinclude

12 Aug 2013: Cont. Dynamical Sys. 28, 1345–1367. 24. Figure 3.4: The errors for h(t) for ω = 200π (top row) and ω = 2000π(bottom row): from the left 0, 1 and

9 Jan 2013: N 2)(7N 11)ρ (N 1)(7N2 27N 24)ρ2. (N 3)(N 2)(2N 1)ρ3],.