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1 - 10 of 21 search results for katalk:za33 24 |u:www.dpmms.cam.ac.uk where 0 match all words and 21 match some words.
  1. Results that match 1 of 2 words

  2. ex2.dvi

    https://www.dpmms.cam.ac.uk/~sjw47/RepTh2.pdf
    22 Feb 2012: g]| 1 21 42 56 24 24α 14 2 0 1 0 0β 15 1 1 0 1 1γ 16 0 0 2 2 2.
  3. ex2.dvi

    https://www.dpmms.cam.ac.uk/~sjw47/Mich2012ex2.pdf
    25 Oct 2012: g]| 1 21 42 56 24 24α 14 2 0 1 0 0β 15 1 1 0 1 1γ 16 0 0 2 2 2.
  4. NON-TRIVIALITY OF TORSION UNIVERSAL CHARACTERISTIC CLASSES OF…

    https://www.dpmms.cam.ac.uk/~or257/Torsion.pdf
    1 Oct 2012: Oscar Randal-Williams, Mathematical Institute, 24-29 St Giles’, Oxford, OX1 3LB, United.
  5. gps212.dvi

    https://www.dpmms.cam.ac.uk/study/IA/Groups/2012-2013/gps212.pdf
    24 Oct 2012: Find all the subgroups of the cyclic group Cn. 8. Show that the symmetric group S4 has a subgroup of order d for each divisor d of 24, and find
  6. numset22012.dvi

    https://www.dpmms.cam.ac.uk/study/IA/Numbers%2BSets/2012-2013/numset22012.pdf
    23 Oct 2012: Do there exist integers x and y with3528x 966y = 24?
  7. ex2.dvi

    https://www.dpmms.cam.ac.uk/study/II/RepresentationTheory/2011-2012/ex2.pdf
    21 Feb 2012: CG(g)| 1 21 42 56 24 24α 14 2 0 1 0 0β 15 1 1 0 1 1γ 16 0 0 2 2 2.
  8. grm20123.dvi

    https://www.dpmms.cam.ac.uk/study/IB/GroupsRings%2BModules/2011-2012/grm20123.pdf
    23 Feb 2012: X4 2X 2, X4 18X2 24, X3 9, X3 X2 X 1, X4 1, X4 4.
  9. DIFFERENTIAL GEOMETRY, D COURSE Gabriel P. Paternain Department of ...

    https://www.dpmms.cam.ac.uk/~agk22/dg2_Paternain.pdf
    28 Nov 2012: 2.6. Theorema Egregium. Theorem 2.24 (Theorema Egregium, Gauss 1827). The Gaussian curvatureK of a surface is invariant under isometries. ... where. W(t) :=αs(t)s. s=0. 23. 24 3. CRITICAL POINTS OF LENGTH AND AREA.
  10. Exp1051new.dvi

    https://www.dpmms.cam.ac.uk/~md384/expose-chr.pdf
    19 Jul 2012: trχ. u= |χ|2/g. We obtain. (24) trχ =2. φ. φ. u,. ... Thisψ defines now a mapping [0, δ] S2 Ŝ. 1051–24. 5.2.
  11. Lectures.dvi

    https://www.dpmms.cam.ac.uk/~sjw47/RepThLectures.pdf
    26 Apr 2012: Thus〈χ,χ〉 = 1/24(42622812302) = 2. Thus if we decompose χ = niχiinto irreducibles we know. ... We can then complete the character table using column orthogonality: We notethat 24 = 12 12 32 32 χ5(e).

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