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26 Jun 2024: For example, we. have. m2K+. m2K0. m2. =mu mdmu md. (5.24). ... corrections, we can generalise (5.24) to. (m2K m2K0) (m2 m20). m20.

26 Jun 2024: integral as. n 4. (2)3 eµ. Z 1. 0. dp p2ep2/2m =. mkBT. 22. 3/2eµ (2.24). Let’s try to interpret this. Read naively, it seems to tell ... anti-aligned to give 3 dierent spin 1 states. With these two amendments, our expression for the number density (2

31 May 2024: They solvedtheir lubrication equations (24)–(32), again by an expansion in a small Deborah numberWe 1, going to the first correction. ... p/. (1. c). p 1. De. H = 21/22. 23/24. Figure 1.

26 Jun 2024: 0 for all S(r) and R(r) (4.24). This is clearly satisfied if R and S are finite at the origin.

26 Jun 2024: Tr T ART BR. =1. 2I(R)AB. (4.24). The Dynkin index is related to the quadratic Casimir C(R), which we previously defined.

31 May 2024: S T)µ1.µp1.r1.q1.s. = Sµ1.µp1.qT1.r. 1.s (2.24). Given an (r, s) tensor T , we can also construct a tensor of lower rank (r

31 May 2024: 1 1. 2He. i!t. (5.24). where, as we mentioned previously, we should take the real part of the right-hand-side. ... S1(0)2 S2(0)2 = R2. The solutions (5.24) tell us how these geodesics evolve.

31 May 2024: should identify. g00(x) (1. 2Φ(x). c2. )(1.24). where Φ(x) is the Newtonian gravitational field. ... 1.24) but with a linear gravitational potential Φ of the kind that we would invoke for.

31 May 2024: 1.4.1 The Metric on the Higgs Branch 23. 1.4.2 Constructing the Solutions 24. ... in 5 1 dimensions is a sigma-model on a hyperKähler target space [24] which, for.

31 May 2024: ṙ2 Ve(r) = E2 (4.24). but this time with the eective potential. ... This tells us that the particle follows a null geodesic. The equation (4.24) gets replaced.