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25 Jan 2007: Geodesic Deviation (23). Eij = j gi. Tidal Tensor (24). Now the gravitational field is conservative, curl g = 0, and so we may introducethe Newtonian Potential by. ... 24. Cop. yrig. ht. 200. 6 U. nive. rsity. of C.

19 Oct 2007: subtraction,r = 1, with 12, 24, 48 and 96 terms respectively. ... 24. Huybrechs, D. & Vandewalle, S. (2006), ‘On the evaluation ofhighly oscillatory integrals byanalytic continuation’,SIAM J.

25 Jan 2007: mis. sion. P.H.Haynes Mathematics IA Algebra and Geometry Michaelmas Term 2002 24.

25 Jan 2007: iqt qxx 2rq2 = 0irt rxx 2r2q = 0. (4.3.24). The reduction r = σq̄, σ = 1, yields the celebrated NLS equation (1.2). ... 24. Cop. yrig. ht. 200. 7 U. nive. rsity. of C.

13 Apr 2007: The second inclusion follows by Theorem VIII.24 ([RS72], p. 290)if we can show that PnAPn A in the strong resolvent sense. ... PROOF. Now, (i) follows from the fact that A1,n A strongly (see Theorem VIII.24 in[RS72], p.

25 Jan 2007: ithou. t per. mis. sion. where D = 0E; H = 10B: (24)The latter vectors are used to describe non-trivial electrical and magnetic properties ofmedia for which and are callled permittivity ... We might ask: can we obtain an understanding of the elementary

15 Feb 2007: rkxj (1)αj erkxj ] = 2ν. k=1. a[αj ,sj ]k cosh(rkxj ). Likewise,. Sα[2s1x f](1) =d. j12sjxj [e. xj (1)αj exj ]g(0). 24.