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17 Jun 2019: c k cot ka = 0. Find the minimum value of V0 for this equation to have a solution. ... Giventhat. 〈x〉 =1. 2k(ka tan ka),. discuss briefly the possibility of 〈x〉 being greater than a.

30 May 2024: KA Hogan, KLP Warburton, AGC Graham, JA Neufeld, DR Hewitt, JA Dowdeswell, RD Larter. – ... KA Hogan, KLP Warburton, AGC Graham, JA Neufeld, DR Hewitt, JA Dowdeswell, RD Larter.

31 May 2024: University of Cambridge. Li Ka Shing Centre. Robinson Way. Cambridge. CB2 0RE. ... University of Cambridge. Li Ka Shing Centre. Robinson Way. Cambridge CB2 0RE.

30 Aug 2019: 2. 1 (i) If A > 0 and N is a positive integer, define KA,N : T2 R by. ... and1. (2π)2. T2. KA,N (s, t) ds dt = 1. By considering functions of the form.

30 May 2024: CJB BROOKES, KA BROWN. – Proceedings of the London Mathematical Society.

30 May 2024: Publications. Modular curves and Néron models of generalized Jacobians. BW Jordan, KA Ribet, AJ Scholl. –

31 May 2024: Lab/Department. Tavaré Lab/CRUK CI. Address. Cancer Research UK Cambridge Institute University of Cambridge Li Ka Shing Centre Robinson Way Cambridge CB2 0RE. ... Martin Miller, Cancer Research UK, Cambridge Institute, University of Cambridge, Li Ka

4 Aug 2022: D,Pa] = iPa, [D,Ka] = iKa,[Pa,Mbc] = i(δabPc δacPb), [Ka,Mbc] = i(δabKc δacKb),[Ka,Pb] = 2i(δabD Mab),. ... Mad,Mbc] = i(δabMcd δacMbd δbdMca δcdMba). with D, Mab, Pa and Ka being the generators of dilations, rotations, translations, andspecial

30 May 2024: A Atoufi, KA Scott, ML Waite. – Physical Review Fluids. (2020).

17 Jun 2019: Let. KA = {X Mnn(R) | [A, X] = 0}LA = {[A, X] | X Mnn(R)}. ... Show that KA and LA are linear subspaces of Mnn(R). If A and B are similar, showthat KA = KB and LA = LB.