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3 Jun 2024: difference is op(1). The actual proof is much more technical (mainly becauseestimation error complicates the selection event). ... References. 26/28. Assumptions in the paper II. Assumption. (Accuracy of treatment model) ‖µ̂t µt‖ = op(n1/4).

3 Jun 2024: 1. cov(Ai, g(Zi)). R3. =1pn. nX. i=1. (Zi, Ai, Yi) op(1). ... This implies. that:pn(̂ ) = 1p. n. nX. i=1. (xi) op(1) (14).

3 Jun 2024: Assumption. I ‖µ̂t µt‖2 = op(n1/4);I ‖µ̂y µy‖2 = op(1);I ‖µ̂t µt‖2 ‖µ̂y µy‖2 = op(n1/2).

3 Jun 2024: RemarksBy assuming f0 and f are differentiable at τ. λ and (f0/f ). ′(τλ) > 0, we show in the paperthat τ̂λ,n,m τλ = Op((n m)1/3).

3 Jun 2024: where R(Pn,P) = oP(1/n) is a negligible remainder term. See blackboard:.

3 Jun 2024: Lecture Notes on Statistical Modelling. Qingyuan Zhao. December 2, 2021. Website for this course: http://www.statslab.cam.ac.uk/qz280/teaching/modelling-2021/. Copyright c2021 Dr Qingyuan Zhao (qyzhao@statslab.cam.ac.uk). This document should be

3 Jun 2024: Lecture Notes on Causal Inference(with corrections). Qingyuan Zhao. May 30, 2022. Website for this course: http://www.statslab.cam.ac.uk/qz280/teaching/causal-2020/. Please contact me if you find any mistakes or have any comments. Copyright c2022 Dr