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17 Jun 2019: Let K denote the 2n2n matrix with n copies of J1 on the diagonal,and zeros elsewhere, and suppose that KA = AK.

17 Jun 2019: Giventhat. 〈x〉 = 12k. (ka tan ka),. discuss briefly the possibility of 〈x〉 being greater than a. ... Hint: consider the graph ofka cot ka against ka.]. Part IB, 2010 List of Questions.

26 Nov 2019:  Gavin Ka Chun Cheung (High Energy Physics).  Antonio Girão (DPMMS).

17 Jun 2019: MATHEMATICAL TRIPOS Part II 2006. List of Courses. Number TheoryTopics in AnalysisGeometry and GroupsCoding and CryptographyStatistical ModellingMathematical BiologyDynamical SystemsFurther Complex MethodsClassical DynamicsCosmologyLogic and Set

17 Jun 2019: cosh kx cosh ka),. where k is a constant such thatlk = 2 sinh ka. ... Let K denote the 2n2n matrix with n copies of J1 on the diagonal,and zeros elsewhere, and suppose that KA = AK.

17 Jun 2019: E =1. 2(E0 E1 4 A cos ka). 1. 2. (E0 E1)2 16 A2 cos2 ka.

20 Jul 2021: 1. ktan. ka. 2= 1. ltanh. la. 2. where. k =. 2mE. 2> 0 and l =. 2m(U0 E). 2> 0. (ii) Suppose that initially U0 = 0 and the particle is in

17 Jun 2019: E =12(E0 E1 4A cos ka). 12. (E0 E1)2 16A2 cos2 ka.

17 Jun 2019: tanh (κa). κa=. tan (ka δ0). ka. where κ2 = γ2 k2.

17 Jun 2019: Let. KA = {X Mnn(R) | [A, X] = 0}LA = {[A, X] | X Mnn(R)}. ... Show that KA and LA are linear subspaces of Mnn(R). If A and B are similar, showthat KA = KB and LA = LB.