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  1. Results that match 1 of 2 words

  2. collection_45.ps.CFs1-1

    www.tcm.phy.cam.ac.uk/~nrc25/SEMINARS/rotating_lattice_amsterdam.pdf
    22 Jul 2009: 1/7 3/7 2 2 7 0.437 911/7 3/7 3 3 7 0.745 13301/7 3/7 4 4 7 0 [0.2753] 20.5k1/7
  3. Correlated Phases of Atomic Bose Gases on a Rotating ...

    www.tcm.phy.cam.ac.uk/~gm360/talks/rotating_lattice_Boulder.pdf
    11 Jun 2009: 2 Hilbert spc dim. 1/7 2 6 2 7 0.437 911/7 3 9 3 7 0.745 13301/7 4 12 4 7 0 [0.275] ... 841 29251/9 4 16 4 9 0 [0.152] 58.9k1/9 4 16 6 6 0.306 58.9k1/9 5 20 5 9 0.459 1.2M. •
  4. 16.1. PROBLEM SET I 197 Answers: Problem set I ...

    www.tcm.phy.cam.ac.uk/~bds10/aqp/ans1.pdf
    14 Oct 2009: The time is given byt = L/v = L. m/2E, where L = 20 mm and m and E are the mass and energy.
  5. 22 Nov 2009: Synopsis: Lectures 20-24. 15 Scattering theory. Elastic scattering; cross section; method of particle waves; Bornapproximation; scattering of identical particles.
  6. lectures

    www.tcm.phy.cam.ac.uk/~bds10/aqp/lec1_compressed.pdf
    21 Oct 2009: Synopsis: Lectures 20-24. 15 Scattering theory. Elastic and inelastic scattering; method of particle waves; Bornapproximation; scattering of identical particles.
  7. lectures

    www.tcm.phy.cam.ac.uk/~bds10/aqp/lec2_compressed.pdf
    21 Oct 2009: 2 , leading to bound state energy E = ma2V 20.
  8. lectures

    www.tcm.phy.cam.ac.uk/~bds10/aqp/lec2.pdf
    12 Oct 2009: 2 , leading to bound state energy E = ma2V 20.
  9. lectures

    www.tcm.phy.cam.ac.uk/~bds10/aqp/lec1.pdf
    8 Oct 2009: Synopsis: Lectures 20-24. 15 Scattering theory. Elastic and inelastic scattering; method of particle waves; Bornapproximation; scattering of identical particles.
  10. lectures

    www.tcm.phy.cam.ac.uk/~bds10/aqp/lec3_compressed.pdf
    21 Oct 2009: mωsin(ωt). Consider dynamics of a (real) wavepacket defined by φ(x) at t = 0.Suppose we know expectation values, p20 = 〈φ|p̂2|φ〉, x 20 = 〈φ|x 2|φ〉,and ... φ|p̂2(t)|φ〉 = p20 cos2(ωt) (mωx0)2 sin2(ωt). and similarly 〈φ|x̂
  11. lectures

    www.tcm.phy.cam.ac.uk/~bds10/aqp/lec3.pdf
    14 Oct 2009: φ|p̂2(t)|φ〉 = p20 cos2(ωt) (mωx0)2 sin2(ωt). and similarly 〈φ|x̂ 2(t)|φ〉 = x 20 cos2(ωt) p20. ... φ〉, x 20 = 〈φ|x 2|φ〉,and we want to determine 〈φ(t)|p̂2|φ(t)〉.In Heisenberg representation, 〈φ(t)|p̂2|φ(t)〉 =

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