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23 Dec 2021: Therefore, we rewrite our expression as. p = 100a0(g′V)1/2 x3/20 t1. ... tmax = T1β1A1/2γ 5/20 , (4.2)for T1 a dimensionless constant to be determined.

13 Apr 2011: y (mm). u (m. m/s. ). t=3 mint=5 mint=12 mint=20 min. ... FIG. 20. The minimum flow rate required for steady flow isestimated by Eq.

5 Mar 2008: 023104-2 D. Takagi and H. E. Huppert Phys. Fluids 20, 023104 2008. ... 023104-4 D. Takagi and H. E. Huppert Phys. Fluids 20, 023104 2008.

26 Sep 2011: 20 = 0"874 K25 , (1)t. where C2o (c25) signifies the diffusivity at 20C (25C). ... 22). The system (20) to (22) is now linear and has solutions o f the form.

16 Jul 2010: The tank was made o f 1 cm thick Perspex and was 20 20 50 cm deep. ... However, the temperature difference between the layers allowed. Fig. 2. Photograph at time 20 minutes shows buoyant compositional plumes rising from the porous medium.

11 Apr 2013: a) (b). buoyant fluid ambient fluid. 56 cm. 2, 5, 10or 20 cm. ... 0 5 10 15 20 250. 0.2. 0.4. 0.6. 0.8. 1.

18 May 2017: M =πa2C1/γ p1/γ u=πa2C1/γ(. kµ. )p1/γ. dpdz. (2.19a,b). Thus. p/pD [1H(z)/H(L)]γ/(1γ) (2.20)= (1z/L)γ/(1γ) ... 19:. 20:. 21:. 22:. ikona:. 751:. 752:. 753:. 754:. 755:. 756:.

9 Mar 2004: a)35. 30. 25. 20. 15. 100 100 200 300 400 500. ... Volume number. Page. s pe. r pa. per. (b)30. 25. 20.

30 May 2006: 0 20 40 60 80 100 120 140 160. t (9 FIGURE 2. ... 796 H. E. Huppert and J. E. Simpson. 0 10 20 30 40 50 60 70.

5 May 2006: 10. 5. 0 5 10 15 20. Figure 1. A shadowgraph image of the developing cells after 7 min. ... 1 48.2 20.3 20.3 7 1.47 1.1 4250 1.1 0.73 48.2 20 20.3 40 0.85 2.6 1810 2.7