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21 Apr 2004: 5th SOHO workshop Oslo, 17-20 June 1997. Bromage, B.J.I., G. Del Zanna, C. ... Pike, 1997: GIS calibration study with a plasma diagnostic method 5th SOHO workshop Oslo, 17-20 June 1997.

21 Apr 2004: Respir. Physiol. 15: 1-38, 1972. 20.

2 Mar 2004: 4π0. LL. dzx20 y. 20 (z z0)2. =µ. 4π0. [sinh1. z z0x20 y. ... 20. }. This is true for arbitrary locations x0, so replacing x0 by x we obtain.

1 Oct 2004: g = (9.78032 0.005172 sin2 ϕ 0.00006 sin2 2ϕ)(1 z/a)2. Mean surface value, ḡ = π/20. ... 25 298 ” 3.820 293 ” 4.20 273 ” 5.2. -30 243 ” 8.4.

20 Jul 2004: For a > 20 the energy depends on theradius as E 1.65 a2.9. ... 10. 15. 20. a. -. -. -. --. 0.7 0.8 0.9 1 1.1b.

10 Mar 2004: Suppose that the former requires 12 n. 2 operations and the latter 10n; thenthe first algorithm is quicker for n < 20.

17 Sep 2004: 0 20 40 60 80 1000. 1. 2. 3. 0 20 40 60 80 1002. ... 1.5. 1. 0.5. 0. 0.5. 1. 0 20 40 60 80 100.

25 Jun 2004: Gross, NuovoCimento 20, 454 1961! 4 C.A. Jones and P.H. Roberts, J. ... Acad. Sci., Ser. III 325, 195. 1997!20 W.H. Raymond and H.L.

19 Nov 2004: We performed numerical integrations of (20) with the time derivative 2it restoredto the left-hand side. ... 20. )v0. 2[2H v0 u20v0 2U zu0] O( 4) = 0, (B.5).

25 Jun 2004: p / 4) is shown in Fig. 3. Initially the center of the rarefactionpulse is 20[Fig. ... rarefactionpulses and the straight-line vortex att = 35 that are initially a dis-tance of 20 healing lengths apart.

25 Jun 2004: is l 5 20. The solutions starting with the thirdpanel possess vorticity and evolve into equally spaced vortex rings. ... In these computationswe use e 5 0.3 and l 5 60,30,20,15.

19 Jan 2004: 20 10 0 10 2020. 10. 0. 10. 20. 20 10 0 10 2020. ... 10. 20. 20. 010. 20. 10 20. 0. 0.25. 0.5. 0.75.

8 Oct 2004: 20). Here γ 0.577216 is Euler’s constant. When we approximate (19) for kh 1, we obtain(18). ... Phys. A: Math. Gen. 4 55[19] Saffman P G 1992 Vortex Dynamics (Cambridge: Cambridge University Press)[20] Schwarz K W 1988 Phys.

26 Jan 2004: 0. 0.002. 0.004. 0.006. 0.008. 20 40 60 80 100. omega. ... omega. 2e–06. 3e–06. 4e–06. 5e–06. 20 40 60 80 100. omega.

29 Nov 2004: The mass of the kink is given by. Mkink = r(χ+ χ) = r(mj mi) (20). ... The 4d theory contains dyons. The 2d theory also contains dyonic kink objects, asfirst noted 10 years ago by Abraham and Townsend [20].

25 Jun 2004: Gross,Nuovo Cimento 20, 454 1961!; L.P. Pitaevskii, Sov. Phys.JETP 13, 451 1961! ... 20# C.W. Gardiner et al., Phys. Rev. Lett. 81, 5266 1998!; M.J.Davis, C.W.

14 Jul 2004: obtain. (4.20) r(z) = u[z0] u[z0,. , zn](z z0) (z zn).We obtain (4.17) by equating the coefficients of zn in (4.20) and the product of

11 Oct 2004: 20] B.F. Hutton, Cardiac Single–Photon Emission Tomography: Is Attenuation Correc-tion Enough? ... Prob. 20, 175 (2004). [31] T. Hebert, R. Leahy, M. Singh, Fast MLE for SPECT using an Intermediate PolarRepresentation and a Stopping Criterion, IEEE

25 Mar 2004: . . . 0 0 0 20 0 2 00 2 0 02 0 0 0.

14 Nov 2004: . . . . (4.20). The technique of the previous paragraph is employed only if at least one ofthe signs sk, k = 1, 2,. , ... We. 20. write t instead of MOVE, in order to retain the notation of Section 4.

23 Apr 2004: In long drums (some of the model experimentshave been with very short drums which permit just a monolayer of particles), Fauvredescribes in chapter 20 an axial instability which leads to a ... For thin layers of grains,Fauvre shows in chapter 20 that air

7 Jan 2004: 2eTt H et = 1 αβ τ2. Hence, by. taking determinants of the matrix equation (2.20), we obtain the condition. ... 20. defined by formula (2.12), where α = eTt Het and σ = αβ τ2, the value of σ being.

30 Sep 2004: Batchelor’s textbook, eq. (7.1.20)). The fact that small Kmeans radian wavelength k1 À 2b suggests that the disturbance should see the whole shear layeras being thin; i.e. ... Rev. Fluid Mech., 20, especially pages381–384. 9. Suppression of shear

17 Jun 2004: ω. 500480400. 20. 10. 440420. 30. 40. Figure 2.1: The error for QA1 (bottom) and three different Filon-type methodsQF1 (from the second plot up), scaled by ω.

8 Mar 2004: 2=. e2. 20. (G. x. )2,. and we calculate G/x as in the worked example in the next section. ... e2. 20. x20. 4π2(x20 (y y0)2 (z z0)2. )3 dy dz = = e216π0x20.