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22 Jan 2019: 25.0. 37.5. 50.062.575.0. Viscosity (mPas). F. 0.00. 0.100.05. 0.150.20. 0.350.300.25. Forward velocity (m. ... The swimmers were driven at 2 Hz with a field strength of 20 mT in all experiments, unless stated otherwise.

6 Feb 2019: 20. 30. 40. 50. 60. c2 ΦΦO. The operator Φ2 decouples from OPE precisely at Φ = 2/3. ... 20). Our CT is consistent with exact results from localization on a squashed sphere:Imamura, Yokoyama ’11.

6 Feb 2019: region. 10 20 30 40 50cT3.0. 3.1. 3.2. 3.3. 3.4. 3.5. ... These bounds are computed with jmax = 20 and = 19 (orange), = 17 (black), and = 15 (light brown).

6 May 2019: J. Fluid Mech. 720 5-14. 5. [20] M.J. Golding, H.E. Huppert, J.A.

11 Jul 2019: in the twistor space plays a role in physics is theamplituhedron of [20]. ... Math.Phys. (N.Y.) 53, 032502 (2012). [20] N. Arkani-Hamed and J. Trnka, The amplituhedron, J.

27 Nov 2019: Example sheet 4 Presentation 20 Jan. 2020, 2-3:30pm, MR15. Exercise 1 (Gaussian model)Assume that we observe measurement F = AU N, where A : Rd Rk is a known

4 Nov 2019: Biofluidmechanics of reproduction. Ann. Rev. FluidMech. 2006; 38: 371–94. [20] Fauci L. ... Proc. Natl. Acad. Sci. USA. 2011; 108: 19516–20.[46] Lovely P. S.

6 May 2019: ĥ3. P4@ĥ@x̂. @ 5ĥ@x̂5! = x 1, (2.20). D:. 0343. 7D. ... L 93 3121/134/13, (3.4a). D:. 0343. 7D. DD. 20. 183. 64.

6 Feb 2019: 2= 1, 20 = 1. For example in Ginsparg’s CFT notes one finds.

6 Feb 2019: the errorsf(x) Nn=0 f̂nϕn(x) for N = 10, 20, 30 and 40. ... 15. Figure 3.2: MT errors for example (3.9) with N = 10, 20, 30, 40.

28 Aug 2019: cm. Planck Scale. Energy. eV eVeV. ConstantCosmological. eV. Observable Universe. 20 billion light years. ... µ. @L. @(@µA). = @2A @(@A) = @µ(@µA @Aµ) @µF µ (1.20).

6 May 2019: 10–20. 10–2 100 102. 10–1 100 101. 10–10. 100. 0 0.1. ... For example, in figure 5(c) the critical Péclet number liesbetween 15 and 20.

18 Dec 2019: ˛0; t/, and. J1 D. Z 20. cos 0.0/2 C r2 C r0. ... 22rr0 cos 0. 32 d0;(2.4a). J2 D. Z 20. 0/2 C r2 C r0.

6 Feb 2019: temperature / energy. SU(3)SU(4) SU(2). 20. • This is all for the specific boundary condition.

23 Nov 2019: Z = 2 8 8 2 = 20) etc. On the other hand, atoms with one electron missing from their highest energy level tend.

6 Feb 2019: Lattice at Trento April 2–6, 2012. The identifications lead (Belle [20]) to. ... Northwestern University 20 K. K. Seth. Lattice at Trento April 2–6, 2012.

14 Nov 2019: 3ϵ3r′2h16ζ k4. (. kdr′hdt. h(k) 2r′hdk. dtm(k). ). O(ϵ4), (20). ... 19), (20) and (25) to determine the net dis-placements from one period of deformation.

23 Nov 2019: 1, 0〉H =12. (|〉e |〉p |〉e |〉p) , (6.20). while applying JH a second time gives. ... In state (6.20), we are. certain to find that the z-component of the spins of the electron and proton are ‘antiparal-.

6 Feb 2019: Can be recovered beyond the Standard Model. N. Uraltsev (Siegen ) Loopless dn and charm CP violation ECT Trento April 5 2012 20 / 29. ... m2π2(mumd )mc. 1.2102 21029. c̄σGu: 20 d (SM)n (right-handed charm), 80 d(SM)n (left-handed charm).

27 May 2019: equations (2.20) as. KTT KTR Ri K(0)TFKRT KRR K. (i)RF Ri. ... From equations (4.16), (4.17), (4.20) and (4.21), we obtain critical angular velocities,.

20 Oct 2019: Phys. 13, 073021 (2011). 20. Michelin, S., Lauga, E. & Bartolo, D.

6 May 2019: We observe good data collapse in an intermediate time period (approximately2 6 T 6 20). ... 10 cm, (c,d) xi = 15 cm, and (e,f )xi = 20 cm.

30 Oct 2019: Genetic modification couldremove these behaviors [17,20–22] but often has unintended effects. ... 0 1 20. 0.2. 0.4. 0.6. 0 1 2 30. 0.2.

6 Feb 2019: Lenz, April 3rd 2012 - p. 20. Semi leptonic CP-asymmetries afs and Γd. ... B1 = 1.100.20. B2 = 0.790.10. ǫ1 = 0.020.02. ǫ2 = 0.030.01.

11 Jul 2019: 20]. We begin in section 2 by discussing the theory of conformal embedding class 1. ... 20 q where ð0 is ð on the unit sphere (which is independent of r) and.

6 Feb 2019: 20. 40. 60. 80. 100. 0 0.005 0.01 0.015 0.02 0.025. ... 0 10 20 30 40 50 60 70 80 90 100Hyperfine splitting (MeV).

27 May 2019: P 8p3R2. Fh ie Mh ie. Mh ie 2 8p3 R a bj jbj j2 (20). ... 2 s1 for a bead of radius R = 20 mm andf C 0.48 pN, in good agreement with eqn (43) which predictsDe C 15 802 mm.

22 Jan 2019: 2469-990X/2019/4(1)/013101(20) 013101-1 2019 American Physical Society. PANAYIOTA KATSAMBA AND ERIC LAUGA. ... 013101-8. HYDRODYNAMICS OF BACTERIOPHAGE MIGRATION …. ez Fhead = 6π μahU, (20)ez Mhead = 6π μahωp.

22 Jan 2019: d 0. d/d 0. General case. 0 10 20 30a/d0. 101. ... 0. 0.5. a =. 20. 1.0. 1.5. 2.0. 0. 0.5a. = 20.

6 Feb 2019: 20/26. Borcherds to Kac-Moody. E8bb b b b b b b.

6 Feb 2019: R1. 0 0.05 0.10 0.15 0.20 0.250. 0.2. 0.4. 0.6. 0.8. ... R̃1 =3. 4ln. (f1k1. ) ωspin z = LM. R̃1. 0 0.05 0.10 0.15 0.20 0.25.

6 Feb 2019: 3AdS R. AdS R horizon3. 3. horizon2. Only one scalar in supergravity is active, φ in the 20′ of SO(6); it is dual to Oφ =tr(2|Z1|2 ... Holographic Fermi surfaces 20 S. Gubser. 4-d cases are a bit more intricate:. #

22 Jul 2019: y. y. y. y. x0.5 1.0 1.5 -30 -20 -10 0 10 20 30. ... 0.010. -60 -40 -20 0 20 40 60t x. -0.4R. -0.100.10.4.

6 Feb 2019: So the series {Aα,Am,Wα,Fmn} solve the non-linear EOM! C.R. Mafra (DAMTP) Non-linear SYM 25.03.2015 20 / 26.

19 Jul 2019: 1.4.2 A Patchwork of Gauge Fields 20. 1.4.3 Monopoles and Angular Momentum 21. ... These. are satisfied by the monomials,. 0 = wMe|w|. 2/4l2B ) Lz 0 = M 0 (1.20).

19 Jul 2019: We define the Rabi frequency as. = eE0 h 1|x| 2i (8.20). ... However, the Rabi frequency is proportional to the. amplitude of the electric field (8.20).

19 Jul 2019: r? = r (B̂ r) B̂. Integrating (3.20), we find. r?(t) = r?(0) eB. ... k̇|. We can use (3.20) to relate |k̇| to the perpendicular velocity,.

6 Dec 2019: ρ =1. Z(β)eβH =. 1. Z(β). n. eβEn|En〉〈En| , (10.20). where in the final expression we have inserted a complete set of H eigenstates.

6 Feb 2019: c). 0 10 20 30 400. 0.5. µf t. III Tf>Tc /µf=0.47. ... 20. • let us study the structure of quasi-normal modes about the final state.

28 Aug 2019: For example, we have the one-particle states. |p, ri = br †p|0i (5.20).

6 Feb 2019: 0 10 20 30 40 50. 1.0. 1.5. 2.0. 2.5. 3.0.

6 Feb 2019: 20. 82 nonvanishing diagram types using N = 4 sYM BCJ form.

22 Jul 2019: ht. H3hx 2. hx. provided x N H 3, (20). giving height and extent scales h H/(1 λ) H 1/2 t 1/2 and x N H 3/2 ... 4 km, η = 1020 Pa s and ρ = 2400 kg m3, respectively, where the underthrusting plate hasan elastic thickness of Te = 20 km, Young’s

6 Feb 2019: Sn =1. 1 n log Trn. (0.19). Trn = h(zi)(zf)iCn/Zn (0.20). ... log. R. ". cL cR. 6.  (0.19). cL 6= cR (0.20).

6 May 2019: L(t ) = 0.97[. (12µ)4QT B9. σ 13. ]1/30t 2/15. (20). ... Appl. Phys. 96, 3429 (2004). [20] Z.-Q. Wang and E. Detournay, The tip region of a near-surface hydraulic fracture, J.

6 Feb 2019: I The number of supersymmetries preserved [Duff] are. 1, 2, 3, 4 , 5, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 32.

14 Nov 2019: Two routes have been identified tobreak symmetries and enable propulsion: i) the chemicalpatterning on the surface of the particle, as used in mostexperiments with “Janus” particles [19, 20, 28, 21]; ii) ... ρ =a. 1 µ2cosh τ µ , z =. a sinh

28 Aug 2019: U(t, t0) = T exp. i. Zt. t0. HI(t0) dt0. (3.20). ... 3.21). Expanding out the expression (3.20), we now have. U(t, t0) = 1 iZ.

6 Feb 2019: See non-linear field equations as some anomaly cancellation condition. T Adamo (DAMTP) Scattering eqns SUGRA 24 March 2015 20 / 23.

4 Jun 2019: IEEE Signal Processing Magazine,35(1):20–36, 2018. [16] X. Ma, B. Li, Y. ... Mathematical Intelligencer, 20:7–15,1998. [29] D. Song, K. Eykholt, I. Evtimov, E.