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  2. 25 Nov 2011: T̄. (νB2H 3/2W 3/2. gV 20. )1= 4. 9 sin θ(a1/2 a1/2 tan1/3 θ )3,. ... V̄ = V0(t/T̄ )1/2, (5)using Eqs. (2)–(4). Note that T̄ V 20 from Eq.
  3. 2902 J . Phys. Chem. 1984,88, 2902-2905 combination of ...

    www.itg.cam.ac.uk/people/heh/Paper62.pdf
    26 Sep 2011: 5) Huppert, H. E.; Manins, P. C. Deep-sea Res. 1973, 20, 315-23. ... 7 = 0.287. The cross-terms are 20 times less than the smallest main term.
  4. Application of gravity currents to the migration of CO2 in…

    www.itg.cam.ac.uk/people/heh/Paper218.pdf
    25 Nov 2011: A cutoff of either 20% or 40% of the total concentration was used to determine the position of the front. ... A cutoff of either 20% or 40% was used to determine the front position.
  5. gl044728 1..5

    www.itg.cam.ac.uk/people/heh/Paper223.pdf
    13 Apr 2011: H 20 m,motivated by the Sleipner site in the North sea [Bickle et al.,2007]. ... FCO2 DDCO2. HSh DCO2. kgD. 4=5 DH. 1=5. ’ 20 kg m2 yr1.
  6. SydneyPapers

    www.itg.cam.ac.uk/people/heh/SydneyPapers.pdf
    24 Aug 2011: 3.3mm per year, remarkably uniformly for at least the last 20 years. ... so to influence the result in 10, 20, … years’ time we need to act now.
  7. flm1100071a

    www.itg.cam.ac.uk/people/heh/Paper228.pdf
    21 Oct 2011: r10 20 30 40. r. t. 0. 0.4. 0.8. 1.2. Vel. ... 5 10 15 20 25 30. rf. (b)(a). Figure 5. Experimental comparison.
  8. 13 Apr 2011: y (mm). u (m. m/s. ). t=3 mint=5 mint=12 mint=20 min. ... FIG. 20. The minimum flow rate required for steady flow isestimated by Eq.
  9. PII: 0011-7471(73)90056-9

    www.itg.cam.ac.uk/people/heh/Paper15.pdf
    26 Sep 2011: 20 = 0"874 K25 , (1)t. where C2o (c25) signifies the diffusivity at 20C (25C). ... 22). The system (20) to (22) is now linear and has solutions o f the form.
  10. flm1100021a

    www.itg.cam.ac.uk/people/heh/Paper227.pdf
    21 Oct 2011: m). 8. 4. 0. 0. 20 40 60 80. 40 6020 80 100. ... 4. 4.2. 10. 15. 20. 25. 8 12 16. 5 10 15.
  11. flm1000491a

    www.itg.cam.ac.uk/people/heh/Paper225.pdf
    18 Jan 2011: φ+. x. x=0. φx. x=0. 4. 1 y2=. (23π. )1/2λ̄φ. 1/20. ... 3.20). Substituting the similarity solution for h from (3.16) and (3.15), we find that.
  12. flm1000488a

    www.itg.cam.ac.uk/people/heh/Paper224.pdf
    18 Jan 2011: R. Lister. –40 –20 0 20 40. x. 0. 0.2. 0.4. ... Thesink is resolved by a 20 cell pattern arranged to roughly approximate a cylindrical fissurein the cap rock.
  13. 10 Mar 2011: 00 þ 01 þ ð Þþ 10 þ 11 þð Þþ 2 20 þ 21 þ ð Þþ , ð28cÞ. ... 2,1k 2 þk2. C. sinð zÞ þðz1Þ. @T fk: ð42Þ. Finally, at O(20) we have.
  14. flm1100110a

    www.itg.cam.ac.uk/people/heh/Paper229.pdf
    21 Oct 2011: 6. 7. 20 40 60 80 1000. 0.2. 0.4. 0.6. 0.8. ... 1.0. Ave. rage. sat. urat. ion. B. 20 40 60 80 100.
  15. PII: 0198-0149(81)90135-7

    www.itg.cam.ac.uk/people/heh/Paper41.pdf
    26 Sep 2011: 14o[50 ' r4oo0 ' 15o5 ' F - - T - -. -. - I. 4,o 441o 40' • 8 8 4 7 4 0 '. o 196 •8851 f. o to 20 L _ _ _ - - __ J. ... I,l,,,l,lll/lllllll///lllll/[Itll E - 5 ,. 4814 m 4758 m. I APR IO ZO I MAY I APR IO 20 I MAY.

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