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23 May 2018: Iserles (ed.), Acta Numerica 20, Cambridge Univ. Press (2011). A. Iserles (ed.), Acta Numerica 19, Cambridge Univ.

30 May 2018: 20] Holographic Q-Lattices. JHEP 1404 (2014) 040 arXiv:1311.3292 [hep-th]. Aristos Donos and Jerome Gauntlett.

13 Nov 2018: Q =. . q00,00 q00,10 q00,01 q00,20 q00,11 q00,02q10,10 q10,01 q10,20 q10,11 q10,02. ... q01,01 q01,20 q01,11 q01,02q20,20 q20,11 q20,02. q11,11 q11,02q02,02. . (2). 2.

28 Sep 2018: 2nd order BC for ω0 with Re = 10 and N = 10, 14 and 20. ... 1. u. x. N=10. 14. 20. 28. 40. Agree to visual accuracy.

1 Feb 2018: 2nd order BC for ω0 with Re = 10 and N = 10, 14 and 20. ... 1. u. x. N=10. 14. 20. 28. 40. Agree to visual accuracy.

7 Oct 2018: cresc. 1. 15. 20. 25. 30. ❲ ❲ ❲❲ ❲❲ ❲ ❲ ❲ ❲ ❲ ❲ ❲. ❲ ❲ ❲ ❲ ❲ ❲ ❲ ❲ ❲ ❲ ❲ ❲ ❲ ❲. ❲❲ ❲ ❲ ❲ ❲ ❲ ❲ ❲ ❲ ❲ ❲ ❲ ❲ ❲ ❲ ❲ ❲ ❲ ❲ ❲ ❲ ❲ ❲. ❲ ❲ ❲ ❲ ❲

31 Jan 2018: 0.6. 0.8. 1. 1.2. 0 10 20 30 40 50 60 70 80. ... psi. iteration. 1.01.7. 1.751.8. For N = 20 Gauss-Seidel needs 500 iterations,whereas SOR with optimal r 1.75 needs 20.

31 Jan 2018: 0.6. 0.8. 1. 1.2. 0 10 20 30 40 50 60 70 80. ... psi. iteration. 1.01.7. 1.751.8. For N = 20 Gauss-Seidel needs 500 iterations,whereas SOR with optimal r 1.75 needs 20.

29 Jan 2018: Error is satisfying u = 0 (N = 20) as function of t. ... u. x. N=302014. s-w, 28. Re = 10 and N = 14, 20 and 30.Also result from ψ ω formulation at N = 28.

31 Jan 2018: with N = 10, 14, 20, 40 and 56. 2e-05. 4e-05. ... Error decreasing as 0.27x4,i.e N = 20 gives 2 106 cf 2 103 for 2nd order.

31 Jan 2018: with N = 10, 14, 20, 40 and 56. 2e-05. 4e-05. ... Error decreasing as 0.27x4,i.e N = 20 gives 2 106 cf 2 103 for 2nd order.

11 Oct 2018: Error is satisfying u = 0 (N = 20) as function of t. ... u. x. N=302014. s-w, 28. Re = 10 and N = 14, 20 and 30.Also result from ψ ω formulation at N = 28.

19 Jan 2018: 0 5 10 15 20 25 30. ’mres8l2i’ u ($13):5’mres8l1i’ u ($12):5’mres8l3i’ u ($14):5.

8 Aug 2018: LILO within the domain is uniform (20), butaccount for the energy associated with the. ... When NBo. 40. 30. 5=.520 So 20. 10e 10. 100 101 102 103 104dH/dt (gaussas).

4 Feb 2018: I only 3 modes per wave for 1% accuracy. cf FD 40 pts at O(x2), 20 pts at O(x4).

16 Nov 2018: Zworski[20, 21]. Introduction Schrödinger and PDEs Discrete operators Numerical Examples Conclusion Definitions.

19 Jan 2018: 2.2 Free field theory 14. 2.3 Perturbation theory 17. 2.3.1 Feynman diagrams 20. ... D eS[]/. (1.20). evaluates the map acting on |'0i 2 H and ending on |'1i 2 H.

20 Jul 2018: this issue was aired more than 20 years ago by. Adrian Parsegian and Robert Austin (Parse-.

8 Jan 2018: diameters) long with t = 0, 0.25, 0.5, 1, 2.5, 5, 10, 20 and Topt = 29.35 D/U (going downwards: flowis from left to right) where U is ... Red dots indicate thetimes (t = 0, 20, 60 and 100) where cross-sections of the total flow (left: 8 contours across [1

2 Nov 2018: 3.20). On the other hand, if m and n go to infinity in case (6), we consider the expression. ... 20. Figure 3.3: log10 |dm,n| (the blue dotted line) and its asymptotic approximation (thered line), for n = 0 (the top left), m = 0 (the top right), m = n

3 Apr 2018: O(h4)︷ ︸︸ ︷iΛ [ψ]1,1(h) 2i. 〈2xµ2,1(h). 〉2, (2.20). whereψ(h,ζ,ξ) = ζ ξ h3. ... Magnus–Lanczos. In Figure 4.3 (right) and Figure 4.4 (right) we show the errorsin exponentiating the order six Magnus expansions (with and without

19 Jan 2018: Error is satisfying u = 0 (N = 20) as function of t. ... u. x. N=302014. s-w, 28. Re = 10 and N = 14, 20 and 30.Also result from ψ ω formulation at N = 28.

24 Jul 2018: Compressive Imaging (CI), U = ΨHadΦdwt 256256 @ 12.5%. MRI, U = ΨdftΦdwt 10241024 @ 20%. ... S1: Best for 256x256. S2: Best for 2048x2048. 6.73%7.30%. 21.3%20.5%. Recovery error.

13 Apr 2018: As a sanity check forcotton, μ 0.3–0.4 [4,5], and thus, hΘi 20. ... 20] M. Abramowitz and I. A. Stegun, Handbook of MathematicalFunctions (Dover, New York, 1965).

14 May 2018: 2Fµ dx. µ dx(7.20). where Fµ are the curvature components. Recall that AU is a matrix–valued 1-form, so.

31 Dec 2018: G = F pV = E pV TS (4.20). This is a Legendre transform of F , this time swapping volume for pressure: G = G(T, p). ... already seen in Section 1.4.1. From its definition (4.20), we see that the Gibbs free. –

13 Dec 2018: For example, without further approximation,evaluation for a scatterer of around 220 by 20 wavelengthscan be carried out in around 100 minutes using 32processors on the SunFire machine. ... 0.05 0.05 0.2 0.6 1.0 1.4 1.8. Fig. 1 Surface current amplitudes

8 Aug 2018: Received 1 September 1995; accepted 20 December 1995! Molecules at the air–water interface often form inhomogeneous layers in which domains ofdifferent densities are separated by sharp interfaces. ... Hr! 5p. 2r2lnr! 20! and. Gij r! 5 2 d i j lnr!

3 Apr 2018: N =1. 2π. Σ. f. (2.20). This is an integer equal to the first Chern number of the vortex linebundle L Σ, and we shall assume that this integer is ... N,. where N is the vortex number defined by (2.20). If the vortex equations(2.16) and (2.17) are

27 Nov 2018: 8.20). 6An equivalent expression is λ(s,m21,m22) = [s (m1 m2)2][s (m1 m2)2].7We need the symmetry factor because merely integrating over all the outgoing momenta

1 Feb 2018: 1st order BC for ω0 with Re = 10 and N = 10, 14 and 20. ... 1. u. x. N=10. 14. 20. 28. 40. Agree to visual accuracy.

27 Nov 2018: 1.20). Finally, noting that Ep = p0 allows us to write the dot product appearing in the exponentials asiEpt ip x = ipµxµ = ip x.

13 Dec 2018: 1997 Acoustical Society of America.@S0001-496697!03703-X#. PACS numbers: 43.20.Fn, 43.20.Mv, 43.30.Hw@ANN#. nsemismiceThthaceinionti-. ... An5an ,bn!, Cn5cn ,dn!, 20! wherean , bn , cn , dn are given by11!

31 Jan 2018: 0.6. 0.8. 1. 1.2. 0 10 20 30 40 50 60 70 80. ... 0. 0.2. 0.4. 0.6. 0.8. 1. 1.2. 0 10 20 30 40 50 60 70 80.

13 Dec 2018: heightλ/20. most surface geometries, and can easily be reduced further with higher order. ... 20. 1 Introduction. 2 Formulation of equations. 2.1 Formal solution and splitting series.

13 Dec 2018: 3. The query condition is set as querying“Peak wave number” with the condition “< 20.0” througha Web form shown in Fig.

25 Oct 2018: 0 5 10 15 20 25 30. ’mres8l2i’ u ($13):5’mres8l1i’ u ($12):5’mres8l3i’ u ($14):5.

13 Dec 2018: Retaining just the first term in the iterative series (11),. ψ = L1ψinc, (20). ... height λ/20. Figure 7: Real part of surface field on waveguide at two frequencies.

10 Mar 2018: In the recent work,20 some connections between the Painlevé property and Lie point sym-metries have been uncovered. ... Nonlinear Math. Phys. 20, 110 (2013).19 Koenigs, M. G., Sur les Géodesiques a Intégrales Quadratiques.

13 Dec 2018: ψ̃ = (C′0 C′1)(C0 C1)1ψinc, (20). and then solving as before and comparing terms with (19).

13 Dec 2018: H2(x,z;x',z')dx' r. --actF(x,x,)B 3/2 exp{ikh '(x•) [z- h(x,) ]}. (20). where C and Sare again the cosine and sine Fresnel integrals, ... 0.02•. 0.015. 0.0•5. 0.0•0. (al a. 0.25. 8.20. 0.15. 0.0•. I.

13 Dec 2018: d f•: k2h2(x,)cos2 0 I2(x) - e&Sx '. 2a•x_x,•x', (20) and. ... k3 O)dkxS] --k2h(x)cos 20--i-•- h2(x)cos 3. (23) We must now find the mean of. •.

13 Dec 2018: 21). Now from eq. (20). E(X,x) =〈h(X). α2π. d. dx. ... Soc. Lond. A 446 (1994) 1-20. (12) C. Qi, Z. Zhao, W.

30 May 2018: spectrum. Example 1. 0 10 20 30 40 50 60 70 8010 -15. ... 10 -10. 10 -5. 0 10 20 30 40 50 60 70 80n.

4 Feb 2018: I only 3 modes per wave for 1% accuracy. cf FD 40 pts at O(x2), 20 pts at O(x4). ... cf FD 40 pts at O(x2), 20 pts at O(x4). Differentiation exact to shortest mode.

31 Jan 2018: with N = 10, 14, 20, 40 and 56. 2e-05. 4e-05. ... Error decreasing as 0.27x4,i.e N = 20 gives 2 106 cf 2 103 for 2nd order.

6 Dec 2018: 2017-present (Assistant professor since 2013). Professor of Mathematics (20% position)University of Oslo, Norway2014-present.

22 Jan 2018: Q2 n1=2? L. 1=2x1=2G1=20 ð1 " q1=2Þhpl! 2þ G0. 2pl. " #2; (44). ... 20=ð2plÞ. 2 þ F2ah2=ðplÞ2. G20=ð2plÞ2 þ F2e h2=ðplÞ. 2! 1=2" 1; (47).

28 Sep 2018: 1st order BC for ω0 with Re = 10 and N = 10, 14 and 20. ... 1. u. x. N=10. 14. 20. 28. 40. Agree to visual accuracy.

19 Oct 2018: I only 3 modes per wave for 1% accuracy. cf FD 40 pts at O(x2), 20 pts at O(x4).