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21 - 30 of 41 search results for TALK:PC53 20 |u:www-keeler.ch.cam.ac.uk where 0 match all words and 41 match some words.

  1. Results that match 1 of 2 words

  2. 4–1 4 Coherence Selection: Phase Cycling and Gradient Pulses ...

    https://www-keeler.ch.cam.ac.uk/lectures/phasen_a4.pdf
    1 Feb 2001: 4–20. phase cycle it in such a way as to select a particular value of p.

  3. 4–1 4 Coherence Selection: Phase Cycling and Gradient Pulses ...

    https://www-keeler.ch.cam.ac.uk/lectures/phasen_letter.pdf
    1 Feb 2001: 4–20. phase cycle it in such a way as to select a particular value of p.

  4. Chapter 9 letter

    https://www-keeler.ch.cam.ac.uk/lectures/Irvine/chapter9.pdf
    12 Mar 2002: 9–20. sampled at regular intervals. After transformation the resulting spectrumdisplays correctly peaks with offsets in the range –(SW/2) to (SW/2) where SWis the spectral width which is given

  5. main.dvi

    https://www-keeler.ch.cam.ac.uk/lectures/Irvine/chapter3.pdf
    5 Mar 2002: a) (b). (c). -20 -1010 20. -1. -0.5. 0.5. 1. -20 -10 0 10 20. ... 0.5. 1. -20 -10 10 20. -1. -0.5. 0.5. 1. MxMy.

  6. select/ALL/5

    https://www-keeler.ch.cam.ac.uk/lectures/EMBOselect.pdf
    23 Jul 2002: 4–20. them to the edge of the spectrum so that they are less likely to obscurewanted peaks.

  7. Chapter 9 a4 /2

    https://www-keeler.ch.cam.ac.uk/lectures/understanding/chapter_9.pdf
    24 Feb 2004: 9–20. them to the edge of the spectrum so that they are less likely to obscurewanted peaks.

  8. C:/Documents and Settings/jhk10/My Documents/NMR Course 2004/../NMR…

    https://www-keeler.ch.cam.ac.uk/lectures/understanding/chapter_2.pdf
    24 Feb 2004: 2–16 NMR and energy levels. 3424 1213. 12 34. 0 20 10040 60 80. ... frequency (Hz) –ν0,1. ν0,2 = –90. ν0,2 = –50. ν0,2 = –20.

  9. main.dvi

    https://www-keeler.ch.cam.ac.uk/lectures/Irvine/chapter4.pdf
    5 Mar 2002: 4.13. tacqtacq /20. 0 π/4π/8 π/2phase. Fig. 4.13 The top row shows sine bell and the bottom row shows sine bell squared weighting functions fordifferent choices ... Suppose that the transmitter is placed in the middle of the shift range andthat a 90

  10. C:/Documents and Settings/jhk10/My Documents/NMR Course 2004/../NMR…

    https://www-keeler.ch.cam.ac.uk/lectures/understanding/chapter_3.pdf
    24 Feb 2004: RF. acq. 90˚ 180˚. τ τ. 2τ. Fig. 3.20 Pulse sequence for the spinecho experiment. ... 0.5. 1. -20 -10 10 20. -1. -0.5. 0.5. 1. MxMy.

  11. main.dvi

    https://www-keeler.ch.cam.ac.uk/lectures/Irvine/chapter2.pdf
    5 Mar 2002: 2.6 Strong coupling 2–15. 3424 1213. 12 34. 0 20 10040 60 80. ... frequency (Hz) –ν0,1. ν0,2 = –90. ν0,2 = –50. ν0,2 = –20.

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