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1 - 9 of 9 search results for TALK:PC53 20 |u:www-keeler.ch.cam.ac.uk where 0 match all words and 9 match some words.

  1. Results that match 1 of 2 words

  2. C:/Documents and Settings/jhk10/My Documents/NMR Course 2004/../NMR…

    https://www-keeler.ch.cam.ac.uk/lectures/understanding/chapter_1.pdf
    24 Feb 2004: Such spectra have proved to beenormously useful in structure determination, and are responsible for the ex-plosive growth of NMR over the past 20 years or so.

  3. C:/Documents and Settings/jhk10/My Documents/NMR Course 2004/../NMR…

    https://www-keeler.ch.cam.ac.uk/lectures/understanding/chapter_5.pdf
    24 Feb 2004: 2. = 20 log10. (ωnew1 /2π. ωinit1 /2π. ). This expression can be used to find the correct setting for the attenuator.As the duration of a pulse of a given flip angle ... power ratio in dB = 20 log10. (τinitτnew. ). For example, suppose we have

  4. Ch 6-9 probs /2

    https://www-keeler.ch.cam.ac.uk/lectures/understanding/chapter_6_9_probs.pdf
    24 Feb 2004: d 30 transferred to 20, 30 and 60. e 30 and 60 transferred to 30 and 60.

  5. C:/Documents and Settings/jhk10/My Documents/NMR Course 2004/../NMR…

    https://www-keeler.ch.cam.ac.uk/lectures/understanding/chapter_2.pdf
    24 Feb 2004: 2–16 NMR and energy levels. 3424 1213. 12 34. 0 20 10040 60 80. ... frequency (Hz) –ν0,1. ν0,2 = –90. ν0,2 = –50. ν0,2 = –20.

  6. C:/Documents and Settings/jhk10/My Documents/NMR Course 2004/../NMR…

    https://www-keeler.ch.cam.ac.uk/lectures/understanding/chapter_3.pdf
    24 Feb 2004: RF. acq. 90˚ 180˚. τ τ. 2τ. Fig. 3.20 Pulse sequence for the spinecho experiment. ... 0.5. 1. -20 -10 10 20. -1. -0.5. 0.5. 1. MxMy.

  7. C:/Documents and Settings/jhk10/My Documents/NMR Course 2004/../NMR…

    https://www-keeler.ch.cam.ac.uk/lectures/understanding/chapter_4.pdf
    24 Feb 2004: 4.13. 4–14 Fourier transformation and data processing. tacqtacq /20. 0 π/4π/8 π/2phase. ... Suppose that the transmitter is placed in the middle of the shift range andthat a 90 pulse of width 20 µs is used to excite the spectrum.

  8. Chapter 7/3(A4)

    https://www-keeler.ch.cam.ac.uk/lectures/understanding/chapter_7.pdf
    24 Feb 2004: interpretation of thispeak is that a signal was present during t1 which evolved with a frequencyof 20 Hz. ... Finally, consider the spectrum shown in c. Here there are two peaks, oneat F 1 = 20 Hz, F2 = 80 Hz and one at F 1 = 20 Hz, F2 = 20 Hz.

  9. Chapter 8 a4 /6

    https://www-keeler.ch.cam.ac.uk/lectures/understanding/chapter_8.pdf
    24 Feb 2004: 8–20. At very short correlation times (τc << 1/ω0) there is some spectral densityat the Larmor frequency, but not that much as the energy of the motion isspread over a

  10. Chapter 9 a4 /2

    https://www-keeler.ch.cam.ac.uk/lectures/understanding/chapter_9.pdf
    24 Feb 2004: 9–20. them to the edge of the spectrum so that they are less likely to obscurewanted peaks.

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