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19 Feb 2015: 3.24). = 1sin θ(sin(1 λ)θ R0 sin λθ R1. ), (3.25). ... 7.93). 24. As in the 2 camera case, the eigenvalue λ returns the value of S3 that we are tryingto minimise.

19 Feb 2015: 0〉 1 and |1〉 Iσ2. (24). In this way ψ sits inside the space spanned by {1,Iσk}, (k = 1, 2, 3).

19 Feb 2015: Fig. 4. The Stanford Bunny[24] distorted by the same rotors. Applications of Conformal Geometric Algebra 343. ... In Proceedings of the IFIPTC5/WG5.10 DEFORM’2000 Workshop and AVATARS’2000 Workshop on De-formable Avatars, pages 24–34.

14 Feb 2015: P = 12ψσ1ψ̃ = κ(γ1(γ0 γ3))κ̃. (24). Since σ1 anticommutes with iσ3, while γ0 commutes, P responds at double rateto phase rotations κ 7 κeiσ3θ, whilst the flagpole is unaffected.

19 Feb 2015: D ισ1z ισ2y(3.24). |10〉 ισ1yD ισ1x ισ2z ισ1x. D ισ1y ισ2z|11〉 ισ1y ισ2y. ... 4.24). The first summation is symmetric with respect to spatial reversion and inversion,i.e.

18 Feb 2015: Hanson. Gravitation, gauge theories anddifferential geometry. Phys. Rep., 66(6):213, 1980. 24. ... Class. Quantum.Grav., 2:919, 1985. [24] A. Barducci, R. Casalbuoni, and L.

14 Feb 2015: The vector. X xx0(τ) (24). is the separation vector down the light-cone, joining the observer to the intersectionpoint with the charge’s worldline.

19 Feb 2015: Employing the one-particleidentity. ik1B1ik. 1B1, 5.24. we see that with no sum over a.

19 Feb 2015: H(t) =Ṡ(t). S(t), (24). so that. Γ2 = 1 kr2/S2, (25). ... 0.24. 0.26. 0 0.2 0.4 0.6 0.8 1 1.2. r (arbitrary units).

5 Feb 2015: 24. should look at the equations of motion for the fiducial frame σi = h1(ei),. ... andu = g1(u), (4.24). are conserved. This follows from. u = Enω (4.25)u = Enω.