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9 Nov 2015: We have (P 1)K = 24 equa-tions for K(K 1)/2 = 28 unknowns. ... Dj,k = 0 for |k j| 6. There remain 25 unknowns for the 24 equations.

4 Nov 2015: 24. More terms: matching two regions. At c0:G0 = (R+ R)/2π.

4 Aug 2015: Integral theorems for small-amplitude motion showedthat the superposition of multiple waves could also lead to anenhancement transition for a range of Deborah numbers [24]. ... Liu, and T. R. Powers, Phys. Rev. Lett. 111,068101 (2013). [24] E.

1 Oct 2015: joe. age height. 24.0 1.7. 30 / 191. Naming indexes of a vector. > ... x. [1] 20.00000 24.14214 27.32051 30.00000 32.36068. 62 / 191.

13 Jan 2015: Hence1. ǫ0Q =. S=V. E dS. (24). The right-hand side is the flux of E out of V. ... The statement (24) is Gauss’s Law. It is ofpractical use.Ex. Consider a point charge q at rest at O, and let V be the sphere of radius r centred

9 Nov 2015: shape. y(x) =µg. 2Tx(x L). (7.24). that obeys y(0) = y(L) = 0. –

23 Jul 2015: Received 15 August 2013; accepted 30 January 2014; published online 24 February 2014). ... Toyama,6 A. Treves,24. M. Uellenbeck,16 P. Vogler,11 R. Zanin,18 M. Kadler,12 R.

22 Apr 2015: h r1/5(a2A)1/5, (20). where the prefactor r1/5 z 0.96 corresponds to the only real zeroof a third order polynomial, 16 384r3 24 192r2 10 611r ... DQ0/e ðqe q0Þ deA: (24). Finally, as the swimmer escapes from the colloid surface(step iii) we have the

17 Dec 2015: 2. ) f(x′). ], (2.24). preserving all quartic Hamiltonians.We note that (2.22) has second order accuracy.

4 Oct 2015: This new vibrational modes are called surface phononsdue to their localisation at the surface [24–26]. ... m & N µ(A1W1) s log(N), (24). in order to guaranty successful recovery with high probability, where µ(B) = max1i,jN |Bi,j|2.