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LOADS Name: pt-load Type: Concentrated force Cload _G5, 2, -200.E6. Output, history, frequency=1 node output, nset=_G5 CF2, U2 element output, elset=_G5 E22, S22.

200}; int ways(int X, int C) { //. } int main() { int X; cin >> X; //. }. The coins values are stored in a constant array, and the index (C) of the largest coin is

10. 255. 8. 32. 16. 100. 42. 100. 100. 200. 932. ... 100. 100. 1000. 914. 200. 200. 1000. 3732. 200. 200. 64.

With 200-300 students in each year, organising a paper-based questionnaire becomes prohibitively time-consuming.

2 Sep 2011: F - front R - Rear WLD1F=200. WLD1R=200. WLD2F=200. WLD2R=200. C C----------------------FRONT-REAR WHEEL SPACING WLSP1=5.

Q20.5 : Is it possible to create a plot of size 200 mm x 100 mm from a ABAQUS analysis?.

Yes. Use the TIE option available under MPC (Multi Point Constraint) to tie the respective nodes as illustrated in the figure below :. MPC TIE, 100, 200 TIE, 101, 201. TIE, 104, ... Here the corresponding nodes should appear in the correct order. NSET,

2 Sep 2011: POR END STEP ------------------------------- CONSOLIDATION ------------------------------- STEP,NLGEOM,INC=200 consolidation SOILS,CONSOLIDATION, UTOL=10 1, 5.0E8, 1.E-5, BOUNDARY TOPC, 8, 8, 0.

2 Sep 2011: POR END STEP ------------------------------- step 3 - CONSOLIDATION ------------------------------- STEP,NLGEOM, AMPLITUDE=RAMP, INC=200 consolidation SOILS,CONSOLIDATION, UTOL=10 1.E-8, 5.0E8, CONTROLS, PARAMETERS=FIELD, FIELD=DISPLACEMENT ,0.7,

2 Sep 2011: FREQUENCY=25, POSITION=CENTROID S, E NODE PRINT, NSET=TOPC U, POR END STEP ------------------------------- step 3 - CONSOLIDATION ------------------------------- STEP,NLGEOM, AMPLITUDE=RAMP, INC=200 consolidation SOILS,CONSOLIDATION, UTOL=10 1.E-8,