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4 Solutions of the 1D Schrödinger equation We now ...
www.qi.damtp.cam.ac.uk/files/Adrian/notespart2.completed.2019.pdf6 Nov 2019: 4.24). 36. Hence. either A = 0 , sin(ka) = 0 ,. ψ(x) = B sin(kx) , k =nπ. 2afor n 2 even. ... or B = 0 , cos(ka) = 0 ,. ψ(x) = A cos(kx) , k =nπ. -
Part IB Quantum Mechanics, Michaelmas 2019 Tuesday and Thursday, ...
www.qi.damtp.cam.ac.uk/files/Adrian/notes160520.pdf16 May 2020: those satisfying Eqn. (3.11). 24. 3.3 The 1D Schrödinger equation for a particle in a potential. -
Part IB Quantum Mechanics, Michaelmas 2019 Tuesday and Thursday, ...
www.qi.damtp.cam.ac.uk/files/Adrian/notes311219.pdf3 Jan 2020: those satisfying Eqn. (3.11). 24. 3.3 The 1D Schrödinger equation for a particle in a potential.
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