Search

24 Jul 2023: δjk 12. dR̂jdŝ. dR̂kdŝ. )(ũk (R̂) ũk (ŝ). )dŝ,. (2.24). where R̂i = R̃i(ŝ). ... 3.1.1. Computation of forces and torquesUnder this parametrisation, (2.24) becomes. Ji = η̃s2. [

1 Oct 2016: hydrodynamics and flow sensing. Annu Rev Fluid Mech. (2016) 48:1–24. doi:. ... J Phys Chem. (1927) 31:1663–8. doi: 10.1021/j150281a004. 32. Adapa S, Dingeldein H, Schmidt KA, Herald TJ.

26 Feb 2014: detailed three-dimensional tomographic analysisrevealed that nexins are in fact one and the same with the dyneinregulatory complex, collectively termed the NDRC [24].

26 Jul 2013: 4,5,24–30]. The individual locomotion of spermatozoa was first studiedby G. I. ... Bottom: Variation of the ratio of the minimum to themaximum of the rate of energy dissipation with ka (symbols).

14 Nov 2019: 1 µ cosh τcosh τ µ eρ, (24). and (eτ , eµ, eφ) form a direct orthonormal basis. ... n c = 1 Da c. (45). Here the Damköhler number Da = Ka/κ is a measureof the relative magnitude of reaction and diffusion.

8 Apr 2010: A′ B′ is given in terms of theRicci spinor φA B A′ B′ and curvature scalar = R/24 by. ... Math., 184. (Dekker, 1997).[24] A. G. WALKER. Riemann extensions of non-Riemannian spaces.

25 Jul 2014: Received: 24 May 2013 / Accepted: 25 November 2013Published online: 24 April 2014 – Springer-Verlag Berlin Heidelberg 2014. ... ̂α :=(π̂A′α̂A. )=. (πA′. αA ϒA B′π B′). (4.24). Our approach is very much in the spirit of [2].

20 Jan 2011: We now use(2.16) to find. φAB = 2|K|2 KA′B AA′. (1. ... Substituting (2.24) into (2.23) gives the system (2.18) for the1-forms ei.

7 Apr 2021: ai bj = 2 ij (2.24)? is sometimes referred to as the dual lattice. ... 52 –. The condition (2.24) can also be stated as the requirement that.

31 Dec 2018: 23. 1. z. 4p2+. (3.24). The next part’s a little fiddly. ... 1. 1. 2p2. 3N. V+. which we then substitute into (3.24) to get.

19 Jul 2019: ai bj = 2 ij (2.24)? is sometimes referred to as the dual lattice. ... 53 –. The condition (2.24) can also be stated as the requirement that.

25 Jun 2004: Tothis end we first filter out the high-frequency harmonics byperforming the transformation a ka kmax$12k. ... JETP Lett. 67, 521 1998!#.@23# B.V. Svistunov, Phys. Lett. A 287, 169 2001!@24# M.J.

7 May 2008: 24] for an analogous study of the one component sys-tem). Acknowledgments. ... Low Temp. Phys. 146, 31. (2007).[24] A. Picozzi, Optics Express, 15, 9063 (2007).

16 Jul 2019: eLife 7:e40018. DOI: https://doi.org/10.7554/eLife.40018,PMID: 30033910. Guasto JS, Johnson KA, Gollub JP. ... 2009. The Chlamydomonas Sourcebook. 2nd edition. London: Academic Press.Hinchliff CE, Smith SA, Allman JF, Burleigh JG, Chaudhary R, Coghill LM,

30 Aug 2009: 2007) 24–26% 40%(Ridgwell and Hargreaves 2007) 34%(Montenegro et al. 2007) 52%. ... Kvenvolden KA (1988) Methane hydrate—a major reservoir of carbon in the shallow geosphere.

20 Jan 2017: x = h(y) = 16 y3 c1y c2, (4.24)where c1 and c2 are constants. ... 2012 Wetting of flexible fibre arrays. Nature 482,510–513. (doi:10.1038/nature10779). 9. Wu X-F, Bedarkar A, Vaynberg KA.

3 Feb 2013: Photosynthetically Active Radiation (Fluora; OSRAM) and 10 h in dark at 24 C.Cells were harvested during the exponential growth phase. ... Phys Rev Lett 105(16):168101. 17. Guasto JS, Johnson KA, Gollub JP (2010) Oscillatory flows induced by

18 Mar 2008: eA00fA D 0; (24)eA10fA D 0: (25). Anti-self-dual conformal structures in neutral signature 123. ... 4Other terminology includes neutral hyper-Kähler [28] and hyper-para-Kähler [24]. Anti-self-dual conformal structures in neutral signature 127.

10 Apr 2011: PACS: 87.17.d; 87.16.Ka; 05.45.a; 46.70.De. Keywords: Supercoil; Growth; Elastic filaments; Filamentous bacteria. ... To this end, substitute the constitutive relation(22) into the moment balanceequation (24)tofind the forceF on a cross-section:.

26 Jul 2013: Received 24 May 2002; accepted 17 December 2002; published online 30 June 2003. ... ¤ and compute a matrix F with components fij = cij =( i ¤j ).The minimal-energy stabilizing feedback controller is then given by u = KÀ , whereK = B ¤ F ¡1.