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  2. 17 Mar 2017: Let hA(x) = Px(TA < ) and kA(x) = Ex[TA]. Theorem 2.2. ... kA(x) = 0 x A. QkA(x) =y. qxykA(y) = 1 x / A.
  3. Part III Logic Michaelmas Term 2017 Chapter 1: A ...

    https://www.dpmms.cam.ac.uk/~tef10/cam_only/chapter1.pdf
    25 Oct 2017: C. (24). to. A1.C. (25). DEFINITION 1We say a pair of introduction-plus-elimination rules for a connective £ is har-monious if. ... 24. consider it will be fairly clear how to move from one approach to the other andback.

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