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  1. Results that match 1 of 2 words

  2. Torborg2004

    www.damtp.cam.ac.uk/user/sje30/waverepo/fourplot/Torborg2004/zzz/Torborg2004_2002-09-24-1.html
    28 Jan 2016:
  3. Stephen J Eglen

    www.damtp.cam.ac.uk/user/sje30/pubs.html
    13 Mar 2016: Frontiers in Computational Neuroscience 7:24.
  4. Torborg2004

    www.damtp.cam.ac.uk/user/sje30/waverepo/fourplot/Torborg2004/zzz/Torborg2004_2002-08-24-1.html
    28 Jan 2016:
  5. Stafford2009

    www.damtp.cam.ac.uk/user/sje30/waverepo/fourplot/Stafford2009/zzz/Stafford2009_Beta2KO_37C_Ventral_2008-10-24-0.html
    28 Jan 2016:
  6. www.damtp.cam.ac.uk/user/mem/oldftp/lucidity-supplem.txt

    www.damtp.cam.ac.uk/user/mem/oldftp/lucidity-supplem.txt
    24 Oct 2016: Stuckness. the predecessor of all real understanding.'' [Near end of chapter 24, p.286 in the original edition.] Of course one can be getting on with other things, at least part
  7. Torborg2004

    www.damtp.cam.ac.uk/user/sje30/waverepo/fourplot/Torborg2004/zzz/Torborg2004_2002-09-24-0.html
    28 Jan 2016:
  8. PHYSICAL REVIEW FLUIDS 1, 073201 (2016) Elastohydrodynamic…

    www.damtp.cam.ac.uk/user/gold/pdfs/elasto_synchro.pdf
    1 Nov 2016: large. However, it is well knownthat use of the leading-order approximation of slender body hydrodynamics for larger values of isrobust [24,25]. ... A(τ ) =(. Be2(2k2k4 )τ 3k. 4. 4(2 k2))1/2. (24). 073201-8.
  9. on September 22,…

    www.damtp.cam.ac.uk/user/gold/pdfs/silicachoano_jrsi.pdf
    22 Sep 2016: di-atoms [39]) but would be predicted to have all undergoneinterphase at some point after 24 h. ... Costal strips are producedduring interphase and, therefore, all cells would have com-menced the silicification pathway within 24 h.
  10. Cop yrig ht © 201 6 U nive rsity ...

    www.damtp.cam.ac.uk/user/examples/A5g.pdf
    10 Jun 2016: mis. sion. 4 Surfaces and Surface Integrals 24. 4.1 Surfaces and Normals 24. ... 24 –. Cop. yrig. ht. 201. 6 U. nive. rsity.
  11. doi:

    www.damtp.cam.ac.uk/user/rrk26/Papers/CK13.pdf
    12 Aug 2016: Received 17 July 2012; revised 19 February 2013; accepted 24 February 2013;first published online 28 March 2013). ... 2d(i)(d(i)zn(i) pn1(i)) 2µzn(i)= 0 (3.23)2µβ = 0 (3.24). z2n β2 2 = 0 (3.25)where di is the ith diagonal element of

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