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12 Jul 2002: 24. 4.4 Equation for ϑ1maxIn this case, the rotations vary approximately in a logarithmic manner. ... X. Z. tape measures. original positions. K zz. 1. Figure 5.24: Definition of extensional stiffness in z-direction.

17 Aug 2001: Extracting pattern from scattereddata - applicability of artificial. neural networks to the interpretationof bearing capacity data. bYby John D. McKinley. CUED / D - SOILS / TR.299 (1996). Extracting pattern from scattered data - applicability of

6 May 2004: FOLDING OF WOVEN COMPOSITE STRUCTURES. J.C.H. Yee and S. Pellegrino1. Department of Engineering, University of CambridgeTrumpington Street, Cambridge CB2 1PZ, UK. ABSTRACT This paper investigates one-ply and two-ply laminates made from woven T300

25 Aug 2008: 5th International Conference on Advanced Composite  Materials in Bridges and Structures (ACMBS‐V). Winnipeg, Manitoba, Canada / September 22 – 24, 2008 . SIM TEST RESULTS FOR ARAMID FIBRES Ioannis P. ... The temperature steps were

17 Nov 2000: 20. 3.4 Mass Estimates. 22. 3.5 Discussion. 22. 4 Deployable Reflector 24. ... 24. (Miura and Miyazaki 1990), in which the triangulated net was supported by six telescopic.

10 Jan 2004: US Patent,. 4,942,700. July 24, 1990. [5] Hoberman C. Radial expansion/retraction truss structures. ... mization. International Journal for Numerical Methods in Engineering 1987, 24:359–. 373.

3 Aug 2011: J. Lynch Æ M. D. Bolton ÆR. N. Taylor. Received: 18 September 2006 / Accepted: 28 November 2006 / Published online: 24 January 2007 Springer-Verlag 2007. ... for example in ethyl alcohol the double layer is re-. duced by a factor of (24.3/80)0.5 or

17 Aug 2001: centrifuge model earthquakes. Ph.D. Thesis. Cambridge University, U.K., pp. 24-39. Pilgrim, N.K.

29 Aug 2001: 7. Tower Construction. (52kPa) for about 24 hours. The stre;s on the clay was then doubled every day until a uniform. ... Each of these 3 data sets are divided as. follows: From the start of each record YO shortly after 02:24 are the data caused by the

21 Jul 2008: Received 14 January 2008. Accepted 24 March 2008. Published on the NRC Research Press Web site at cgj.nrc.ca on 29 May 2008.

5 Apr 2007: lx ly (24). The outcome of this calculation is. . Nx.

24 Apr 2003: λ(δ1 δ2)π. (24). Here δ1 and δ2 are the radial displacements of the corners loaded by T1 and T2, respectively;these corner displacements can be estimated from. ... The wavelength predictions are very close.The wrinkle amplitudes have been estimated

3 Aug 2011: A. Bagnold. J. FluidMech. 452, 1–24 (2002). doi:10.1017/S0022112001006577. 11. Itasca Consulting Group : P F C 3 D Version 3.1 User’s Manual.Itasca Consulting Group, Minneapolis

28 Nov 2013: r2. a2þ z. 2. b2 1 (24). where a. b.The focal radius of an ellipse can be expressed as. ... b2 a2 r2f a rhð Þ2. rf rhð Þ2(27). Substituting equation (27) into the general ellipse expression(equation (24)) produces a quartic equation in terms of

30 Oct 2017: Thompson (1962) creep data. Cam clay curve is. creep strength. 24.

15 May 2003: Site 11: Seattle (Gurtowski et al. 1984) [S] Two compression tests on octagonal concrete precast piles of nominal 24 inch (608 mm) diameter are reported (Table 11). ... 1984) table 1 qb/qc (D/40 failure) 0.29 0.24 Chow (1996) interpretation qc (av. /-

30 Jan 2005: W = PE δwsin2θcosθ. (23). But, since. φ =π. 2 2θ (24).

17 Aug 2001: respectively, for the complex Fourier analysis’. (c) I- 24 Fourier descriptors. ... 64 -56 -48 -40 -32 -24 -16 - 8 0 8 16 2 4 3 2 40 4 8 5 6 6 4.

6 Feb 2007: Since the 24 m deepexcavation is very close to nearby streets, utilitiesand structures, extensive field monitoring was imple-mented to observe and document conditions aroundexcavation.

15 Feb 2005: 29 results in:. AArB. x. 12.575.025.01. 24.55.02. 0. %. Eq. 31. ... Technical Report of the University of Cambridge CUED/D-SOILS/TR 334 Page 24.

2 Feb 2006: 24. 35 dq. dĈ. " #C/:. ð4:3ÞTo find equilibrium configurations of the structure, we look for points where. ... K̂ Zv2Û=vq2 v2Û=vq vĈ. v2Û=vq vĈ v2Û=vĈ2. 24. 35; ð4:5Þ. is positive definite.

11 May 2006: n 16-48 64-96 112-145Elements along tendons 100 116 134Elements at equator 30 24 20Number of elements 3460 3216 3072Number of nodes 1831 1725 1671. ... Figures 24(a) and 24(b) show this type ofplot respectively for nCA118-10-290 and nCR118-10-290 balloons

6 Oct 2005: Short-Term Time Records. Unfiltered Data Earthquake. 4. Figure No. CUED/D-SOILS/TR338. 24. ... 24. Data from Test IT06, Earthquake 1. PS.1. PS.2. PS.3. PS.4.

3 Aug 2011: These observations are consistent with thosemade by [24] who considered the importance of soil fabric onsoil properties. ... 431–441. [24] Rowe, P. W., 1972. “The relevance of soil fabric to siteinvestigation practice”.

2 Aug 2011: 04 12 24. Fig. 9. Comparison between load – settlement response withload – relative settlement response of a footing on sand at 1gwith o 10 kPa. ... Footing : particle size ratios between 24 and 1183,and container : footing diameter ratios between

17 Aug 2001: After 24.5 hours the compressed air supply was turned off, resulting in a slow butsteady increase in the inner tub temperature over the next 25 hours. ... TlwrrtumS 40 30 20 10 0 -10 -20 90&tuntton 37 24 15 9 6.5 3.2 1.8 1.0'SatlJntion Moillure calbrlt

17 Aug 2001: po-YE 36 -. i 3 2 -& _t _P-I0, 24 -:: -. --- __l_-_-----.--.l_. - -._.->. /. Technical Report No. CUED/D-SoiWTR288 Sharma I.,. ... it will not produce. 1 1. hm,=. o:(l+ e) (24). The co-efficient of volume change depends on the void ratio as well as the

2 Jul 2007: 24.7y = 263.2. y = 263.224.7 = 10.7cm 11cm. 4. Mark out y on the card and cut away the excess card. ... 0.49A x (d 1) = 11.025 24.5M. Re-arranging gives. M = (0.49A x (d 1) – 11.025) / 24.5.

14 Oct 2003: 10. 735 65.6 1.25 Axial Failed. 11 269 24 0.46 Axial Inertia. ... Slab and asphalt top 24.8m27.64m(0.20.05) m 25kN/m3 4146kN. Crash barrier 21.5m0.1m27.6425kN/m3 207.3kN.

19 Apr 2004: cossin. ψψ. =. b (24). where ψ is the angular orientation of b and ranges π. ... Expanding Equation (23) with Equation (24) and writing the result in matrix form gives the stiffness in the ψ direction TKψ = b Kb (25) where.

17 Aug 2001: 24. Critical state soil mechanics associates rapid geotechnical disasters with soil on. ... 25. Leonards. G.A. (Ed.) (1986). “Special issue on Dam failures.” Engineering Gcoo:,24( 1-4).

17 Aug 2001: Station N-S E-W U-D Epicentral DistanceARC 0.92 0.41 0.35 35CNA 0.77 0.41 0.24 105BUR 0.44 0.31 0.2 130. ... respectively. 24. (N-S). (E-W). (U-D). Figure 3.4.3 Wavelet analysis of ARC signal.

16 Nov 2006: At the end of this step of calculation the equivalent tunnel diameterfrom equation (9) will be 4.24 m. ... The energy calculation is repeatedin the further steps as requested, with VL 2% and D 4.24 m, etc.

17 Feb 2003: α. α. =. =. (24). where I is the rotational inertia of a link. ... Again, the equation gives the average acceleration at time t. Equations (22) and (24) form a linear system of six equations with six unknowns.

3 Aug 2011: two species of burrowing invertebrates can individually increase the. undrained shear strength of clay by about 1kPa after 24 hours.

20 Dec 2013: The excavation. was supported by a 0.7 m thick diaphragm wall 24 m deep. ... 45. & 6 1 7 4538. -24-9:38;. <77. Fig. 6.

1 Mar 2005: C90 2.72 24.76 4.18 39.18 0.274. Table 3. Comparison of optimized Configuration D. ... 24 of 28. Tan & Pellegrino. of given width and thickness, shortening the slits at the end of diameter d1 increases the.

20 Aug 2002: CUED D/SOILS/TR321 White 2002 ________________________________________________________________________________________________________. 24. sample after each addition of fine material revealed that an evolution of a ‘tail’ in the.

2 Apr 2007: 24–33.3“SAMCEF v12.0-03,” Samtech Group, LIEGE science park, Rue des Chasseurs-Ardennais, 8B-4031 Liège (Angleur),.

30 Mar 2004: W = PE δwsin2θcosθ. (23). But, since. φ =π. 2 2θ (24).

2 Aug 2011: Fraction A LB sand Fig. 3a hasa D50 of 2.24 mm. ... CD CL FD FL. 2.24 2.24 0.28 0.28. 87 1,532 1,551 1,386.

28 Nov 2013: Ground Engng 15, No. 1, 16 – 24. Wijeyakulasuriya, C. V.

30 Jul 2002: Calladine studies a physical model of a tensegritystructure with 12 joints and 24 bars, which should be loose with 6 degrees of freedom,according to Maxwell’s rule; yet, it is

30 Mar 2010: environmentaldeterioration sustained load. ACI 440 0.80 - 0.90 0.24 - 0.27. ... The amount of shift log (αT) is determined from the Arrhenius equation [24].

12 Oct 2004: The Hardin &. Drnevich expression yields 24 MPa which, as with the sands, would have been too stiff. ... 24. CUED/D-SOILS/TR336. 17. LoPresti, D.C.F., Jamiolkowski, M., Pallara, O., Cavallaro, A. &

17 Aug 2001: Max=25.3. Mb=-26.4. Max=O.l. Mill=-0.2. Max=lO.S. Mln=-12.3. Mox=S.O. Mill=-9.4. Max=24.9. Mln=-33.6. ... II. SHORT TERMTIME RECORDS. G L e v e l FIG.NO.5 0 24.

28 Feb 2003: Pak. Deployable tensegrity structures.Fourth-year undergraduate project report, 24 May2000. Department of Engineering, University ofCambridge, Cambridge, UK.

17 Aug 2001: 4112% 1. 2. Atlantic MudW cv (m2/yr). 9 0 % 0.229 9 % 0.21107% 0.24. ... Volume vs. Height Relationship in Tanks. 24. Figure 7a. Photograph of Piston Sampler ContainingSample of E-grade Kaolin.

23 Apr 2003: π= (24). The battens and diagonals must provide enough support to the longerons to enforce local buckling.

27 Jan 2009: The tunnel was4.1 m in diameter at a depth of 24 m, and the measurementswere made by means of rod extensometers installed fromanother tunnel (see Fig. ... 18 – 24 100 6 – 12 50 NA. Metasediments 25 – 30 50 20 – 25 25 825Crushed MCB2 20 – 25 50