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15 Aug 2011: 614.2 An example from criminology, and some exercises. 624.3 From recent Mathematical Tripos questions. ... equivalentlylog E(Nij) = const ai bj for some a,b. Thus, in terms of log E(Nij), testing H0 is equivalent to testing a hypothesis which islinear

29 Jul 2011: In the firstsection we recall some results on the Galois representations associatedto automorphic forms. ... If π is ramified, then as above we have for some t > 0.

18 Jul 2011: linear. The useof our methods to compute some elements of X(E/Q)[5] will be describedin future work. ... H1(K, E[2]) = ker(L/(L)2. NL/K K/(K)2). Therefore α has square norm, say NL/K α = α1α2α3 = b2 for some b K.

12 Jul 2011: This is easy to do later. Here, let Vbe some irreducible G-space. ... For 1 6 i 6 n, hgi = gj,some j 6= i, so ith row of [ρreg(h)]B has 0s in every place, except column j – inparticular, the (i,