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7 Jun 2010: NBB = z1. 2Nx2. NAB NBA = zN(1 x)x. (2). where NAB represents both A–B and B–A bonds which cannot be. ... B–B bonds 12zNax2 and A–B B–A bonds zNa(1 x)x where z.

7 Jun 2010: 2). where NAB. represents both A–B and B–A bonds which cannot be dis-. ... a(1 x)2,. B–B bonds 12zN. ax2 and A–B B–A bonds zN.

7 Jun 2010: where NAB represents both A–B and B–A bonds which cannot be distinguished. ... 2, B–B bonds 12 zNax2 and A–B bonds zNa(1 x)x. where z is the co–ordination number.

7 Jun 2010: energy as an AA and a BB bond is broken to create 2(AB)bonds. ... energy in the process of forming AB bonds. The activity is equalto the mole fraction in an ideal solution (Fig.

7 Jun 2010: bonds. An ideal solution is formed when there is no change in energy in. ... the process of forming A B bonds. The activity is equal to the mole.

7 Jun 2010: B–B bonds respectively, and the third and fourth terms the numbers of A–B and B–A. ... bonds may then be obtained by setting ln{}/NAB = 0 (Christian, 1975; Lupis,.

19 Oct 2020: A B B B i i1 i2 i3. <latexit ... number NeAB of A-B bonds:.

12 Oct 2020: The factor of 12 avoids counting A-A or B-B bonds twice. ... the enthalpy of mixing is not zero. The number of A-A, A-B and B-B bonds in a mole of solution.

7 Jun 2010: bonds.4. In ordered crystals, A atoms prefer to be next to B atoms: the enthalpy of ordering HO. ... finding a B atom andx(1 x) is that of finding an A atom next to a B atom.

7 Jun 2010: AB BA 1N N zNx x+ = where NAB represents both A–B and B–A bonds which cannot be distinguished. ... N is the total number of atoms. Notice that the unlike bonds A–B and B–A cannot be distinguished and hence have been consolidated.