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Diffraction and Imaging (all content)

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0. •s. 0. = 1, and so:. |S|. 2. = 2 - 2 cos 2θ = 4 sin. ... rm{i}}{{{bf{x}}sin 2theta } over lambda }} right){rm{d}}x} cr & {rm{ = 2}}{{rm{A}}_0}cos left( {{{pi b sin 2theta } over lambda }} right) cr} $$.
Granular Materials (all content)

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theta _{rm{c}}} = arctan frac{1}{{2sqrt 2 cos (60circ - varphi )}}{rm{ }}]. A proof of this formula is given here. ... B and A are initially at (cos φ', sin φ', 0) and (cos (φ' 60), sin (φ' 60), 0) respectively, while D is initially at. [

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