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15 Apr 2021: M2Plä. a= 1. 6(ρ 3p). (1.24). Second, by taking the time derivative of the Friedmann equation and using the continuityequation to get rid of ρ̇, we can find the ... ̇K = ä2K. ȧ3ä (ρ 3p) (1 3w) , (1.27). where in the second step I used the

16 Apr 2021: na=1. La〈O(k1)O(k2). O(kn)〉 = 0 , (1.1). where La = L(τa,τa, ka,ka) is some linear, possibly differential operator made of func-. ... Then (4.26) becomes[. 3(n 1) na=1. ka. ka. ]〈R(k1)R(k2). R(kn)〉′! = 0 , (4.38).

8 Jul 2021: cells swim [24–28]. Absolute pressure [29], pH [30] and even magnetic field [31] have also. ... Bi = 0.11 0.06 (n = 2),hB/Li = 0.63 0.24 (n = 9)).

25 Aug 2021: 1.2.2 The Scattering Amplitude 22. 1.2.3 Partial Waves 24. 1.2.4 The Optical Theorem 27. ... q. kA(eiqa/2 eiqa/2). Notice that only the combination (r t) appears.

7 Apr 2021: structure. E = C cos(ka). Then the velocity in a constant electric field oscillates as. ... N =. 0. which should clearly be an integer. The quantisation (4.24) due to a background magnetic field.

23 Apr 2021: 1.2.2 The Scattering Amplitude 22. 1.2.3 Partial Waves 24. 1.2.4 The Optical Theorem 27. ... q. kA(eiqa/2 eiqa/2). Notice that only the combination (r t) appears.

7 Apr 2021: ai bj = 2 ij (3.24)? is sometimes referred to as the dual lattice. ... 91 –. The condition (3.24) can also be stated as the requirement that.

7 Apr 2021: ai bj = 2 ij (2.24)? is sometimes referred to as the dual lattice. ... 52 –. The condition (2.24) can also be stated as the requirement that.

7 Apr 2021: structure. E = C cos(ka). Then the velocity in a constant electric field oscillates as. ... N =. 0. which should clearly be an integer. The quantisation (3.24) due to a background magnetic field.

7 Apr 2021: qg = 2πn with n Z (1.24). This is the famous Dirac quantisation condition. ... qg = 2πn with n Z. This, of course, is the Dirac quantisation condition (1.24).