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22 Nov 2011: Tj(x) = cos(j arccos x), j = 0, 1, 2,. ,. and c0 = 1π , cj =. 2π , j 6= 1. ... Given that the polynomials Tj are orthogonal with respect to the weight.

1 Sep 2011: More details on the problems relevant to k;p can befound in [1],[2],[5].Recall that Nj(t) := (tjk tj) [tj; tj1; : : :; tjk] ( t)k1+ ;so that suppNj = (tj; tjk); ... degree p such thatsuppMj;p = (tj; tjp1); Z tjp1tj Mj;p(x)dx = 1;and by!

1 Sep 2011: 2. Condition number and related constantsLet fN̂jg be the B-spline basis of order k on a knot sequence t = (tj), tj < tjk,normalized with respect to the Lp-norm (1 ... p 1), i.e.,N̂j(x) = (k=(tjk tj))1=pNj(x);where fNjg is the B-spline basis which

1 Sep 2011: f (tj ) = g(tj ) on {a = t0 < t1 <. < tn < tn1 = b}. Then, there exists a spline z such that. ... be such thatg(tj ) = p(tj ) on {a = t0 < t1 <. < tn < tn1 = b}. Then, there exists a spline z such that.

1 Sep 2011: APPROXIMATION THEORY:A volume dedicated to Borislav Bojanov(D. K. Dimitrov, G. Nikolov, and R. Uluchev, Eds.)additional information (to be provided by the publisher). Twelve Proofs of the Markov Inequality. Aleksei Shadrin. This is the story of the

1 Sep 2011: x) : 1(yi1) = g(yi1); 01(yi1) = g0(yi1+);ki1(x) : ki1(yi) = g(yi); 0ki1(yi) = g0(yi);and for j such that Tj = Tj ,j(x) : 8><>: (r)j ... Hence 2 S(A0i;1); A0i 2 Xj: Tj=Tj 1:Since i(x) = maxf(x); p(x)g;we change into p at most once in each T j.

1 Sep 2011: The subintervals of and their lengthes will be denoted by. Ij := (tj, tj1), |hj| := tj1 tj. ... Nj = 1, (1.1.1). Mj (x) =k. tjk tjNj(x),. tjk. tj.

13 Apr 2011: i. j. [h(xi ,tj ) f (xi ctj )]2, (2). where h represents the thickness recorded at discrete positionsxi and times tj.

26 Sep 2011: tJ l,t,R. occupied with the failing conductivity cell and Stas S842 to 8853 with the r c p l a c c m e u resistor.

12 Apr 2011: Prescott TJ, Redgrave P, Gurney K (1999) Layered control architectures in robots and.